Cho hai tập hợp A = {0,1,4,7,8,9}, B = {1,2,3,4,6,7,8}.Tập hợp B\A bằng:
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Đáp án
A. {2,3,6}
Lời giải:
B\A là tập hợp các phần tử B có mà A không có. => B\A = {2,3,6}
Answer:
Answer:
See the graph attached. The red arrow represents the shaded area.
Explanation:
The inequality and its solution are given:
The solution set is all real numbers less than or equal to -50.
In a number line, the values less than -50 are all the values that are to the left of -50. Thus, the graph of a ≤ -50 must include -50 and the region to the left of it.
To indicate that - 50 is included, draw a solid point; then, shade the region since it to its left.
Please, see the graph attached. The red arrow represents the shaded area.
Step-by-step explanation:
Answer:false
Step-by-step explanation:
Answer:
The largest possible volume V is ;
V = l^2 × h
V = 20^2 × 10 = 4000cm^3
Step-by-step explanation:
Given
Volume of a box = length × breadth × height= l×b×h
In this case the box have a square base. i.e l=b
Volume V = l^2 × h
The surface area of a square box
S = 2(lb+lh+bh)
S = 2(l^2 + lh + lh) since l=b
S = 2(l^2 + 2lh)
Given that the box is open top.
S = l^2 + 4lh
And Surface Area of the box is 1200cm^2
1200 = l^2 + 4lh ....1
Making h the subject of formula
h = (1200 - l^2)/4l .....2
Volume is given as
V = l^2 × h
V = l^2 ×(1200 - l^2)/4l
V = (1200l - l^3)/4
the maximum point is at dV/dl = 0
dV/dl = (1200 - 3l^2)/4
dV/dl = (1200 - 3l^2)/4 = 0
3l^2= 1200
l^2 = 1200/3 = 400
l = √400
I = 20cm
Since,
h = (1200 - l^2)/4l
h = (1200 - 20^2)/4×20
h = (800)/80
h = 10cm
The largest possible volume V is ;
V = l^2 × h
V = 20^2 × 10 = 4000cm^3
