At constant temperature, if the pressure of the sample of the krypton gas increases to the given value, the volume decreases to 15mL.
<h3>What is Boyle's law?</h3>
Boyle's law simply states that "the volume of any given quantity of gas is inversely proportional to its pressure as long as temperature remains constant.
Boyle's law is expressed as;
P₁V₁ = P₂V₂
Where P₁ is Initial Pressure, V₁ is Initial volume, P₂ is Final Pressure and V₂ is Final volume.
Given the data in the question question;
- Initial volume of the gas V₁ = 75.0mL = 0.075L
- Initial pressure of the gas P₁ = 0.40atm
- Final pressure of the gas P₂ = 2.00atm
- Final volume of the gas V₂ = ?
Now, we substitute our given values into the expression above to determine the new volume of the krypton gas.
P₁V₁ = P₂V₂
V₂ = P₁V₁ / P₂
V₂ = 0.40atm × 0.075L / 2.00atm
V₂ = 0.03Latm / 2.00atm
V₂ = 0.015L
V₂ = 15mL
Therefore, at constant temperature, if the pressure of the sample of the krypton gas increases to the given value, the volume decreases to 15mL.
Learn more about Boyle's law here: brainly.com/question/1437490
#SPJ1
The numbered list support the purpose of the text as It provides a schedule for runners to follow as they train for a 5K race.
<h3>What is a running schedule?</h3>
A running schedule is known to be a simple formula that is used for any great training in terms of plan.
It includes Training three days a week. Therefore, The numbered list support the purpose of the text as It provides a schedule for runners to follow as they train for a 5K race.
Learn more about training from
brainly.com/question/25110079
#SPJ1
The point slope form of the asymptote of the hyperbola is; y - 4 = ±(6/7)(x - 6)
- We are given the equation of the hyperbola as;
[(y + 4)²/36] - [(x - 6)²/49] = 1
- We can rewrite this equation as;
[(y + 1)²/6²] - [(x - 6)²/7²] = 1
- The general equation form of hyperbola is;
[(y - k)²/a²] - [(x - h)²/b²] = 1
- Comparing this general form to our given equation we can see that;
k = -4
h = 6
a = 6
b = 7
- Now the equation of the asymptote of a hyperbola follows the general formula;
y = ±[a(x - h)/b] + k
- Plugging in the relevant values gives us;
y = ±(6/7)(x - 6) - 4
>> y - 4 = ±(6/7)(x - 6)
Read more about hyperbola asymptotes at; brainly.com/question/12919612
