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Finger [1]
3 years ago
10

What is the average rate of change of the function on the interval from x = 0 to x = 5?

Mathematics
2 answers:
bixtya [17]3 years ago
8 0
The average rate is 3^x/2
damaskus [11]3 years ago
6 0

Answer:

Average rate of change = 24.2

Step-by-step explanation:

f(x)=\frac{1}{2}3^x

Average rate of change formula is on interval a to b is

\frac{f(b)-f(a)}{b-a}

Given interval is x=0 to x=5

a=0 and b=5

Average rate = \frac{f(5)-f(0)}{5-0}

f(0)=\frac{1}{2}3^0=\fracc{1}{2}=0.5

f(5)=\frac{1}{2}3^5=\frac{3^5}(2}=121.5

Average rate = \frac{f(5)-f(0)}{5-0}

Average rate = \frac{121.5-0.5}{5}=24.2

Average rate of change = 24.2

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One of the roots of the equation 3x^2+7x−q=0 is −5. Find the other root and q.
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Let the other root of the equation be 'p'. So, we have

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p\times(-5)=-\dfrac{q}{3}\\\\\\\Rightarrow \dfrac{8}{3}\times 5=\dfrac{q}{3}\\\\\\\Rightarrow q=40.

Thus, the other root is \dfrac{8}{3} and the value of 'q' is 40.

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