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artcher [175]
2 years ago
6

Wasted, gta love b____es wasted. wasted, im on these drugs I feel wasted. wasted, get her off my mind when I'm wasted. wasted, I

waste all my time when I'm wasted. wasted, gta love b____es wasted. wasted, im on these drugs I feel wasted. wasted, get her off my mind when I'm wasted. wasted, I waste all my time when I'm wasted. wasted, she do cocaine in my basement. ima doctor but I'm running out of patience. she told me that shes tryna get closer to satan. she be talking to em when she in the matrix.
d__n. why she so demonic? she medusa wit a lil pocahontas. she be lacin on my drugs or something, cause everytime were together I'm unconscious. hol up, lemme be honest. ik i saw her put the perks in my chronics. smokin till my eyes roll back like the old man, just another funeral for her. god d__n.

wasted, gta love b____es wasted. wasted, im on these drugs I feel wasted. wasted, get her off my mind when I'm wasted. wasted, I waste all my time when I'm wasted.


dude I just typed that out, that took so long lol.
pls don't report. free points
Mathematics
2 answers:
zvonat [6]2 years ago
8 0

Answer: 999

Step-by-step explanation:

grin007 [14]2 years ago
7 0

Answer:

yes, mhm the answer is $999.00

Step-by-step explanation:

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Mt. Pleasant elemantry School was collecting canned food. The chart below shows how much food they collected over 3 weeks the ca
n200080 [17]
Just -: by 8 I think
4 0
3 years ago
A circle has the order pairs (-1, 2) (0, 1) (-2, -1) what is the equation . Show your work.
olga55 [171]
We know that:

(x-a)^2+(y-b)^2=r^2

is an equation of a circle.

When we substitute x and y (from the pairs we have), we'll get a system of equations:

\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}

and all we have to do is solve it for a, b and r.

There will be:

\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}\\\\\\
\begin{cases}1+2a+a^2+4-4b+b^2=r^2\\a^2+1-2b+b^2=r^2\\4+4a+a^2+1+2b+b^2=r^2\end{cases}\\\\\\
\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\\\\\


From equations (II) and (III) we have:

\begin{cases}a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\--------------(-)\\\\a^2+b^2-2b+1-a^2-b^2-4a-2b-5=r^2-r^2\\\\-4a-4b-4=0\qquad|:(-4)\\\\\boxed{-a-b-1=0}

and from (I) and (II):

\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\end{cases}\\--------------(-)\\\\a^2+b^2+2a-4b+5-a^2-b^2+2b-1=r^2-r^2\\\\2a-2b+4=0\qquad|:2\\\\\boxed{a-b+2=0}

Now we can easly calculate a and b:

\begin{cases}-a-b-1=0\\a-b+2=0\end{cases}\\--------(+)\\\\-a-b-1+a-b+2=0+0\\\\-2b+1=0\\\\-2b=-1\qquad|:(-2)\\\\\boxed{b=\frac{1}{2}}\\\\\\\\a-b+2=0\\\\\\a-\dfrac{1}{2}+2=0\\\\\\a+\dfrac{3}{2}=0\\\\\\\boxed{a=-\frac{3}{2}}

Finally we calculate r^2:

a^2+b^2-2b+1=r^2\\\\\\\left(-\dfrac{3}{2}\right)^2+\left(\dfrac{1}{2}\right)^2-2\cdot\dfrac{1}{2}+1=r^2\\\\\\\dfrac{9}{4}+\dfrac{1}{4}-1+1=r^2\\\\\\\dfrac{10}{4}=r^2\\\\\\\boxed{r^2=\frac{5}{2}}

And the equation of the circle is:

(x-a)^2+(y-b)^2=r^2\\\\\\\left(x-\left(-\dfrac{3}{2}\right)\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}\\\\\\\boxed{\left(x+\dfrac{3}{2}\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}}
7 0
3 years ago
Someone help me with this
DaniilM [7]

Answer: 7.5

Step-by-step explanation:

3 0
2 years ago
Jerome solves the inequality y–2 ⩽ 9 in one step, writing y ⩽ 11 as the solution. What property best justifies the step he used
DedPeter [7]
The answer is b because he added 2
8 0
3 years ago
3.452 × 100 =-------------
Lilit [14]

Answer:

345.2

Step-by-step explanation:

1: Move 3.452 to the end of the equation

(3.452 × 100) -> (3.452 × 100 = 3.452)

2: Since 100 has 2 zeros, move the decimal point 2 places to the right.

(3.452 × 100 = 3.452) -> (345.2)

Hope this helps!

7 0
3 years ago
Read 2 more answers
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