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alexdok [17]
3 years ago
8

Can anyone help me with this?

Mathematics
1 answer:
Viktor [21]3 years ago
5 0
E. 1/2
With trig functions, multiple x values correspond with the same y value.
Using an initial x value (the principle value), we can find other x values for the same y value, this is what we are are being asked to find in this question.
There are slightly different ways to find these x values (also known as solutions) for each of the basic trig functions.
The x values are in degrees for the basic trig functions.
For cosine, the rule is as follows:
360 - principle value;
this will give what I, personally, like to think of as a secondary principle value (this value is not actually recognised as a secondary principle value, I just like to think of it as such). Anyway, all other solutions can the be found by adding or substrating any integer multiple of 360 to/from the PV and 'secondary PV'.

For your question:
cos60 = 1/2
60 is the x value (PV)
so...
360 - 60 = 300 is the 'secondary PV'
Just to be clear, this means that if I were to find the cos300, I would get 1/2.

That is sufficient for explaining the answer to this particular question but if you wanted to find any other solution, you would just have to do either:
60 + or - n(360)
or...
300 + or - n(360),
where n = any integer
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A camp program charges a registration fee and a daily amount. The total bill for 12 days is $338. The total bill for 19 days is
Artyom0805 [142]

The charge for 30 days will be $720 and for 22 numbers of days of people can attend the camp.

<h3>How to form an equation?</h3>

Determine the known quantities and designate the unknown quantity as a variable while trying to set up or construct a linear equation to fit a real-world application.

In other words, an equation is a set of variables that are constrained through a situation or case.

Given, the cost of the camp program

$338 → 12 days

And,

$506 → 19 days

Slope = (506-338)/(19-12)

Slope = 24

So, the cost per day will be 24

So equation will be

y = 24x

Now,

The charge is for 30 days ⇒

y = 24 (30)

y = $720

And

Number of days of camp could someone attend with a budget of $530⇒

530 = 24x

x = 22.08

Since day could not be a decimal quantity so it will be 22.

Hence "The charge for 30 days will be $720 and for 22 numbers of days of people can attend the camp".

For more about the equation,

brainly.com/question/10413253

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4 0
2 years ago
The amount of radioactive uranium changes with time. The abscissas and ordinates of the points given are the time and amoung of
kakasveta [241]
The answer is <span>A. f(t) = 100(0.25)t
</span>
This may be solved by inserting all points to your answer and sseeing if they work. Since <span>A. f(t) = 100(0.25)t fits with all points, this best represents the relationship between f(t) and t.
</span>

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4 0
3 years ago
A Galapagos tortoise can 1/5 mile in an hour. How many hours would it take the tortoise to walk 1/6?
polet [3.4K]

Answer:

5/6 hours

Step-by-step explanation:

Create a proportion where x is the number of hours it will take to walk 1/6 of a mile:

\frac{1/5}{1} = \frac{1/6}{x}

Cross multiply and solve for x:

1/5x = 1/6

x = 5/6

So, it will take the tortoise 5/6 hours to walk 1/6 of a mile

8 0
3 years ago
(6, 3), (7-4) find the slope<br>​
Hunter-Best [27]

Answer:

-7

Step-by-step explanation:

Y-Y\frac{-4-3}{7-6}

4 0
3 years ago
The vertices of xyz are x (1,-4)
dexar [7]

Answer:

5. The vertices of ΔX'Y'Z' are (-3, -7), (-6, -4), (-1, -2)

6. The vertices of ΔX'Y'Z' are (6, -7), (3, -4), (8, -2)

Step-by-step explanation:

If the point (x, y) translated by T → (h, k), then its image is (x + h, y + k)

#5

In ΔXYZ

∵ X = (1, -4), Y = (-2, -1), Z = (3, 1)

∵ T → (-4, -3)

∴ h = -4 and k = -3

→ Use the rule above to find the image of the vertices of the Δ

∵ X' = (1 + -4, -4 + -3)

∴ X' = (-3, -7)

∵ Y' = (-2 + -4, -1 + -3)

∴ Y' = (-6, -4)

∵ Z' = (3 + -4, 1 + -3)

∴ Z' = (-1, -2)

∴ The vertices of ΔX'Y'Z' are (-3, -7), (-6, -4), (-1, -2)

#6

In ΔXYZ

∵ X = (1, -4), Y = (-2, -1), Z = (3, 1)

∵ T → (5, -3)

∴ h = 5 and k = -3

→ Use the rule above to find the image of the vertices of the Δ

∵ X' = (1 + 5, -4 + -3)

∴ X' = (6, -7)

∵ Y' = (-2 + 5, -1 + -3)

∴ Y' = (3, -4)

∵ Z' = (3 + 5, 1 + -3)

∴ Z' = (8, -2)

∴ The vertices of ΔX'Y'Z' are (6, -7), (3, -4), (8, -2)

6 0
3 years ago
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