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Nat2105 [25]
3 years ago
6

How to find equation of line passing through the points (x,y)​

Mathematics
1 answer:
DochEvi [55]3 years ago
3 0

First you must acknowledge that you are dealing with a line therefore you must write linear equation or linear function in this case.

Linear function has a form of,

y=mx+n

Then calculate the slope <em>m</em> using the coordinates of two points. Let say <em>A(x1, y1)</em> and <em>B(x2, y2)</em>,

m=\dfrac{\Delta{y}}{\Delta{x}}=\dfrac{y_2-y_1}{x_2-x_1}

Now pick a point either <em>A</em> or <em>B</em> and insert coordinates of either one of them in the linear equation also insert the slope you just calculated, I will pick point <em>A</em>.

y_1=mx_1+n

From here you solve the equation for n,

y_1=mx_1+n\Longrightarrow n=y_1-mx_1

So you have slope <em>m</em> and variable <em>n</em> therefore you can write down the equation of the line,

f(x)=m_{slope}x+n_{variable}

Hope this helps.

r3t40

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Hailey is 2 years younger than her sister. If Hailey is h years old, which equation represents the age of her sister, s?
butalik [34]

Answer:

S=H+2

Step-by-step explanation:

OK, so hailey is the variable H. And she is 2 years younger than her sister.

What is the age of her sister?

So we know it has to be, hailey's age + something? = age of her sister.

what is that +something? it's the number "2 years younger" so hailey's age; which is h, plus 2 is equal to her sister's age.

H+2=S

OK, why do we need to add 2? instead of minus two? Because hailey is 2 years younger than her sister, so you want hailey's age. If you were to minus 2, you'd be thinking that hailey is OLDER than her sister. Because if you want to her sister's age, you would have to SUBTRACT 2 because you are OLDER than her. So if you are younger than the sister, you would add to get your sister's age.

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You are a lifeguard and spot a drowning child 60 meters along the shore and 40 meters from the shore to the child. You run along
sukhopar [10]

Answer:

The lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

Step-by-step explanation:

This is a problem of optimization.

We have to minimize the time it takes for the lifeguard to reach the child.

The time can be calculated by dividing the distance by the speed for each section.

The distance in the shore and in the water depends on when the lifeguard gets in the water. We use the variable x to model this, as seen in the picture attached.

Then, the distance in the shore is d_b=x and the distance swimming can be calculated using the Pithagorean theorem:

d_s^2=(60-x)^2+40^2=60^2-120x+x^2+40^2=x^2-120x+5200\\\\d_s=\sqrt{x^2-120x+5200}

Then, the time (speed divided by distance) is:

t=d_b/v_b+d_s/v_s\\\\t=x/4+\sqrt{x^2-120x+5200}/1.1

To optimize this function we have to derive and equal to zero:

\dfrac{dt}{dx}=\dfrac{1}{4}+\dfrac{1}{1.1}(\dfrac{1}{2})\dfrac{2x-120}{\sqrt{x^2-120x+5200}} \\\\\\\dfrac{dt}{dx}=\dfrac{1}{4} +\dfrac{1}{1.1} \dfrac{x-60}{\sqrt{x^2-120x+5200}} =0\\\\\\  \dfrac{x-60}{\sqrt{x^2-120x+5200}} =\dfrac{1.1}{4}=\dfrac{2}{7}\\\\\\ x-60=\dfrac{2}{7}\sqrt{x^2-120x+5200}\\\\\\(x-60)^2=\dfrac{2^2}{7^2}(x^2-120x+5200)\\\\\\(x-60)^2=\dfrac{4}{49}[(x-60)^2+40^2]\\\\\\(1-4/49)(x-60)^2=4*40^2/49=6400/49\\\\(45/49)(x-60)^2=6400/49\\\\45(x-60)^2=6400\\\\

x

As d_b=x, the lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

7 0
3 years ago
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