![( { \frac{4 {x}^{3} }{ {y}^{4} }) }^{ - 2} = \frac{16x {}^{6} }{ {y}^{8} }](https://tex.z-dn.net/?f=%28%20%7B%20%5Cfrac%7B4%20%7Bx%7D%5E%7B3%7D%20%7D%7B%20%7By%7D%5E%7B4%7D%20%7D%29%20%7D%5E%7B%20-%202%7D%20%20%3D%20%20%5Cfrac%7B16x%20%7B%7D%5E%7B6%7D%20%7D%7B%20%7By%7D%5E%7B8%7D%20%7D%20)
![\frac{(4 {x}^{3})^{ - 2} }{ { {(y}^{4} )}^{ - 2} } = \frac{16 {x}^{6} }{ {y}^{8} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B%284%20%7Bx%7D%5E%7B3%7D%29%5E%7B%20-%202%7D%20%20%7D%7B%20%7B%20%7B%28y%7D%5E%7B4%7D%20%29%7D%5E%7B%20-%202%7D%20%7D%20%20%3D%20%20%5Cfrac%7B16%20%7Bx%7D%5E%7B6%7D%20%7D%7B%20%7By%7D%5E%7B8%7D%20%7D%20)
![\frac{ {16x}^{ - 6} }{ {y }^{ - 8} } = \frac{ {16x}^{6} }{ {y}^{8} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B16x%7D%5E%7B%20-%206%7D%20%7D%7B%20%7By%20%7D%5E%7B%20-%208%7D%20%7D%20%20%3D%20%5Cfrac%7B%20%7B16x%7D%5E%7B6%7D%20%7D%7B%20%7By%7D%5E%7B8%7D%20%7D%20)
The power of -2 was mistook as 2.
Answer:
40.5
Step-by-step explanation:
Since QS is an angle bisector then PQs and SQR are similar. Using the similarity theorem;
PQ/PS = QR/SR
45/20 = x/18
Cross multiply
20x = 45 * 18
20x = 810
x = 810/20
x = 40.5
Hence the value of x is 40.5
Answer:
Hi, there your answer
Number 15: 16
Number16: 176
Number 17: 0
Number 18: 12
Number 19: -3
Number 20:-52
Number 21:{−9}
Number 22: {13}
Number 23:{1}
Number 24:{−90}
Number 25:{−2}
Number 26:{−2}
Number 27:{56}
Number 28:{9}
Number 29:{15}
Number 30: {−10}
Step-by-step explanation:
The answer are in bold I don't know if you are looking for the work or the answer???
Hope this helps :)
Answer:
is the fifth term from the given formula.
Step-by-step explanation:
We have been given an explicit formula![a_n=6n-4](https://tex.z-dn.net/?f=a_n%3D6n-4)
we have to find fifth term means we have to find ![a_5](https://tex.z-dn.net/?f=a_5)
So, as to find the the fifth term we will put n=5 in the given explicit formula:
![a_5=6(5)-4](https://tex.z-dn.net/?f=a_5%3D6%285%29-4)
![a_5=26](https://tex.z-dn.net/?f=a_5%3D26)
Hence, the fifth term from the given formula is:
![a_5=26](https://tex.z-dn.net/?f=a_5%3D26)
The value of arc FEH is 234 degrees i.e the major arc FH subtends an angle of 234 degrees at the center.
The value of angle subtended by the major arc FH at the circle will be the half of angle subtended by it on the center,
![\begin{gathered} \angle\text{FGH}=\frac{234^{\circ}}{2} \\ =117^{\circ} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cangle%5Ctext%7BFGH%7D%3D%5Cfrac%7B234%5E%7B%5Ccirc%7D%7D%7B2%7D%20%5C%5C%20%3D117%5E%7B%5Ccirc%7D%20%5Cend%7Bgathered%7D)
Simirally the angle subtended by the minor arc FG on the center is 109 hence it will subtend half angle at the circle,
![\begin{gathered} \angle EHG=\frac{109^{\circ}}{2} \\ =54.5^{\circ} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cangle%20EHG%3D%5Cfrac%7B109%5E%7B%5Ccirc%7D%7D%7B2%7D%20%5C%5C%20%3D54.5%5E%7B%5Ccirc%7D%20%5Cend%7Bgathered%7D)
The value of angle FEH
![\begin{gathered} \angle FEH+\angle FGH=180 \\ \angle FEH+117=180 \\ \angle FEH=63^{\circ} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cangle%20FEH%2B%5Cangle%20FGH%3D180%20%5C%5C%20%5Cangle%20FEH%2B117%3D180%20%5C%5C%20%5Cangle%20FEH%3D63%5E%7B%5Ccirc%7D%20%5Cend%7Bgathered%7D)
Thus, the required value of angle FEH is 63 degrees and the value of angle EHG is 54.5 degrees.