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ioda
3 years ago
10

A statistical procedure used to determine whether observed frequencies at each level of one categorical variable are similar to

or different from frequencies expected, is called the chi-square:
Mathematics
1 answer:
Maslowich3 years ago
4 0

Answer:

<h2>This statement is true.</h2>

In statistics, the chi-square test is used to prove a specific hypothesis, accepting or rejecting the null one. In order to find enough evidence to prove the hypothesis, we compare two group of frequencies, which belongs to two different groups (like a quasi-experimental design, with a control and experimental group). The researcher have set an expected frequency, based on the hypothesis, and then he/she will observe a frequency from the data recollected.

Therefore, by comparing this two frequencies (the expected with the observed), the researcher is able to demonstrate the hypothesis.

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Complete the ordered pairs so that they are solutions of the linear equation 5x + y = -21: (-6, ___), (0, ___), (1, ___).
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<span>5x + y = -21:
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Araceli is trying to decide between three job offers. She created the table below to compare the offers.
inna [77]

Answer:

Difference= $11,280

Step-by-step explanation:

Giving the following information:

Manager at Shop & Save Grocers= Hourly wages $16.50 per hour  

Assistant Manager at Unbelievable Toys= Monthly wages $3,800

Cashier at 7-12 Convenience Store= Yearly wages $43,000

<u>First, we need to calculate the yearly wages, and then compare the results:</u>

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5 0
3 years ago
Evaluate the expression below when x= -2 x+4
ZanzabumX [31]

Answer:

x+4= -2+4

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Step-by-step explanation:

3 0
3 years ago
The authors of a paper describe an experiment to evaluate the effect of using a cell phone on reaction time. Subjects were asked
Serggg [28]

Answer:

a) The 99% confidence interval would be given by (24.409;24.979)  

b) n=464

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Part a

The confidence interval for the mean is given by the following formula:  

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:  

df=n-1=47-1=46  

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,46)".And we see that t_{\alpha/2}=2.01  

Now we have everything in order to replace into formula (1):  

525-2.01\frac{75}{\sqrt{47}}=503.01  

525+2.01\frac{75}{\sqrt{47}}=546.99  

So on this case the 95% confidence interval would be given by (503.01;546.99)

Part b

The margin of error is given by this formula:  

ME=t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

And on this case we have that ME =7 msec, we are interested in order to find the value of n, if we solve n from equation (1) we got:  

n=(\frac{t_{\alpha/2} s}{ME})^2 (2)  

The critical value for 95% of confidence interval is provided, t_{\alpha/2}=2.01 from part a, replacing into formula (2) we got:  

n=(\frac{2.01(75)}{7})^2 =463.79 \approx 464  

So the answer for this case would be n=464 rounded up to the nearest integer  

8 0
3 years ago
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