Considering it's horizontal asymptote, the statement describes a key feature of function g(x) = 2f(x) is given by:
Horizontal asymptote at y = 0.
<h3>What are the horizontal asymptotes of a function?</h3>
They are the limits of the function as x goes to negative and positive infinity, as long as these values are not infinity.
Researching this problem on the internet, the functions are given as follows:
.
The limits are given as follows:
Hence, the correct statement is:
Horizontal asymptote at y = 0.
More can be learned about horizontal asymptotes at brainly.com/question/16948935
#SPJ1
If it cost $200 per month and you are makeing $900 per month you are making money off the machine.
A. Factor the numerator as a difference of squares:
c. As
, the contribution of the terms of degree less than 2 becomes negligible, which means we can write
e. Let's first rewrite the root terms with rational exponents:
![\displaystyle\lim_{x\to1}\frac{\sqrt[3]x-x}{\sqrt x-x}=\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Clim_%7Bx%5Cto1%7D%5Cfrac%7B%5Csqrt%5B3%5Dx-x%7D%7B%5Csqrt%20x-x%7D%3D%5Clim_%7Bx%5Cto1%7D%5Cfrac%7Bx%5E%7B1%2F3%7D-x%7D%7Bx%5E%7B1%2F2%7D-x%7D)
Next we rationalize the numerator and denominator. We do so by recalling
In particular,
so we have
For
and
, we can simplify the first term:
So our limit becomes
Answer:
it clicked by it self sorry can't help
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
For the first one, there is a ratio of change greater than one so that is exponential growth.
The second one has exponential decay but its x is negative making it actually exponential decay even if graphed.
The third one has positive growth over an interval of negative x, so in terms of x there is exponential decay.
The fourth one is neither and if graphed is just points as there is a specific solution set.
In conclusion, the third is exponential decay!
Hope this helps :)
