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svet-max [94.6K]
3 years ago
9

Solve -5.55-8.55c+4.35c for me please

Mathematics
1 answer:
serious [3.7K]3 years ago
7 0

Answer:

− 5.55 − 4.2 c

Step-by-step explanation:

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Figure 14-3
enot [183]
The answer is D. SIS idk how to do this
Ur welcome
5 0
3 years ago
Please help !! I would really appreciate it. brainliest will be given for best answer
faltersainse [42]

Since A is (-7,-4) and C is (7,3) for the x value from a to c is 14 for the y value from a to c is 7

Do 14 x 2/7 which is 4

Do 7 x 2/7 which is 2

then add (-7+4,-4+2) which is (-3,-2)

7 0
3 years ago
Suppose you have a 6-face unfair dice with numbers 1,2,3,4,5,6 on each of its faces. If the probability distribution of throwing
kotegsom [21]

Answer:

D is correct

Step-by-step explanation:

Here, we want to select which of the options is correct.

The correct option is the option D

Since the die is unfair, we expect that the probability of each of the numbers turning up

will not be equal.

However, we should also expect that if we add the chances of all the numbers occurring together, then the total probability should be equal to 1. But this does not work in this case;

In this case, adding all the probabilities together, we have;

1/12 + 1/12 + 1/12 + 1/12 + 1/12 + 1/2

= 5(1/12) + 1/2 = 5/12 + 1/2 = 11/12

11/12 is not equal to 1 and thus the probability distribution cannot be correct

4 0
3 years ago
Alexis sold boxes of homemade granola bars for $8.50 each. It cost her $2.25 to bake and package each box of granola bars. What
scZoUnD [109]

Answer: 6.25 is her profit

Step-by-step explanation: cost-price= protect

2.25 - 8.50=6.25

4 0
3 years ago
Write the explicit formula that represents the geometric sequence-2, 8, -32, 128
maks197457 [2]
Well,  since we know is a geometric sequence, we can always get the common ratio  of it by simply dividing one value by the one behind it... so let's do so, with say hmm -32 and 8  -32/8 = -4  <-- our common ratio

the first term is -2

\bf n^{th}\textit{ term of a geometric sequence}\\\\&#10;a_n=a_1\cdot r^{n-1}\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;r=\textit{common ratio}\\&#10;----------\\&#10;a_1=-2\\&#10;r=-4&#10;\end{cases}\implies a_n=-2(-4)^{n-1}
4 0
3 years ago
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