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Leona [35]
3 years ago
7

PLZ HELP WILL GIVE BRAINLIEST

Mathematics
1 answer:
Leni [432]3 years ago
6 0

Answer:

the company should survey every 5th client that makes an appointment.

the company should have a computer randomly generate a list of 200 clients to survey.

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How many solutions would the following system of equations have​
user100 [1]

Answer: 2.

Step-by-step explanation: Both lines intersect each other 2 times.

3 0
3 years ago
Read 2 more answers
If 80 persons can perform a piece of work in 16 days of 10 hours each, how
eduard

Answer:

The number of men needed to perform a piece of work twice as great in tenth part of the time  working 8 hours a day supposing that three of the second set can do as much  work as four of the first set is:

  • <u>1200 men</u>.

Step-by-step explanation:

To find the answer, first, we're gonna find how many hours take to make the piece of work in 16 days, taking into account each day just has 10 hours:

  • Number of hours to make a piece of work = 16 * 10 hours
  • Number of hours to make a piece of work = 160 hours.

Now, we divide the total hours among the number of persons:

  • Equivalence of hours per person = 160 hours / 80 persons.
  • Equivalence of hours per person = 2 hours /person

This equivalence isn't the real work of each person, we only need this value to make the next calculations. Now, we have a piece of work twice as great as the first, then, we can calculate the hours the piece of work needs to perform it (twice!):

  • Number of hours to make the second piece of work = 160 hours * 2
  • Number of hours to make the second piece of work = 320 hours

We need to make this work in tenth part of the time working 8 hours a day, it means:

  • Time used to the second work = 320 hours / 10
  • Time used to the second work = 32 hours
  • Time used to the second work = 32 hours / 8 hours (as each day has 8 hours)
  • Time used to the second work = 4 days

Now, we know three of the second set can do as much  work as four of the first set, taking into account the calculated equivalence, we have:

  • Work of four workers of first set = Work of three workers of second set
  • Work of four workers of first set = Equivalence * 4 persons.
  • Work of four workers of first set = 2 hours /person * 4 persons
  • Work of four workers of first set = 8 hours.

So, three persons of the second set can make a equivalence of 8 hours. At last, we calculate all the number of workers we need in a regular time:

  • Number of needed workers in a regular time = (320 hours / 8 hours) * 3 persons.
  • Number of needed workers in a regular time = 40 * 3 persons
  • Number of needed workers in a regular time = 120 persons

Remember we need to perform the job not in a regular time, we need to perform it in tenth part of the time, by this reason, we need 10 times the number of people:

  • Number of needed workers in tenth part of the time = 120 persons * 10
  • <u>Number of needed workers in tenth part of the time = 1200 persons</u>

With this calculations, <em>you can find the number of men needed to perform a piece of work twice as great in tenth part of the time  working 8 hours a day supposing that three of the second set can do as much  work as four of the first set is </em><u><em>1200 persons</em></u>.

4 0
3 years ago
The graph shows the commission earned for each week of employment.
frozen [14]

Answer:

A, B, D

Step-by-step explanation:

A is true.  From week 5 to week 11, the curve goes down.

B is true.  After week 11, the curve goes up.

C is false.  The curve passes $320 twice in the first ten weeks, not three times.

D is true.  The curve starts at about $110.

E is false.  As time increases, the graph goes up.  As time decreases, the graph goes down.

8 0
4 years ago
A) 30<br> B) 2.5<br> C)1.5<br> D)2
gulaghasi [49]
Angle 1 and angle 2 are corresponding (they have an equal value). Set the two equations equal to each other, then solve.

40-4x=50-8x
+4x +4x
40=50-4x
-50 -50
-10=-4x
/-4 /-4
10/4=x
5/2=x
2.5=x

ANSWER: B) 2.5





7 0
3 years ago
Read 2 more answers
at 9:00 o saturday morning two bicycylist heading in oppisite directions pass eachother on a bicycle path. the bicyclist heading
miv72 [106K]

39/1.5=26 for the 1.5 hours difference.

divide 26/2=13 for each person.

divide 4/2 for the speed increase of person north. The speeds much average to 13.

subtract 13-2=11 and add 13+2=15 for south and north.

north speed is 15 km per hour and south is 11 km per hour.

7 0
4 years ago
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