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3 years ago

Please help step by step. Solve for x

Mathematics

1 answer:

Eddi Din [679]3 years ago

8 0

Ok so do you have any idea how to start

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2= 1/6 (10x+6) solve the x

azamat

Answer:

x=3/5 or 0.6

Step-by-step explanation:

8 0

3 years ago

Complete a one-paragraph summary of the information provided in the video. Your summary should include information on the coordi

12345 [234]

Answer:

please link video. There are literally billions of videos on the internet. Please link.

Step-by-step explanation:

6 0

2 years ago

The sum of two numbers is 52. The greater number is 4 more than the smaller number. Which equation can be used to solve for the

Arisa [49]

Answer:

x+(x+4)=52

Step-by-step explanation:

Let's name the smaller number x.

The greater number would then be (x+4).

The sum of two numbers means we are adding them together.

The equation we could then set up would be:

x+(x+4)=52

Now we can solve the equation to find the two numbers if needed.

Here is how:

x+x+4=52

Combine like terms.

2x+4=52

Subtract 4 from both sides.

2x=48

Divide both sides by 2

x=24

The smaller number is 24.

24+4=28

The larger number is 28.

6 0

4 years ago

The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 44,663 miles, with a standard

expeople1 [14]

Answer:

The probability is $P(| \= X- \mu| < 199 ) = 0.733$

Step-by-step explanation:

From the question we are told that

The mean mileage of a tire is $\mu = 44663$

The standard deviation is $\sigma = 2594$

The sample size is n = 209

Generally the standard error of mean is mathematically represented as

$\sigma_{x} = \frac{\sigma}{\sqrt{n} }$

=> $\sigma_{x} = \frac{2594}{\sqrt{209} }$

=> $\sigma_{x} = 179.4$

Generally the probability that the sample mean would differ from the population mean by less than 199 miles is mathematically represented as

$P(| \= X- \mu| < 199 ) = P(|\frac{\= X - \mu}{ \sigma_{x}}| < \frac{199}{ 179.4})$

$\frac{\= X -\mu}{\sigma } = Z (The \ standardized \ value\ of \ \= X )$

=> $P(| \= X- \mu| < 199 ) = P(|Z| < \frac{199}{ 179.4})$

=> $P(| \= X- \mu| < 199 ) = P(|Z|< 1.11)$

=> $P(| \= X- \mu| < 199 ) = P(-1.11 \le Z \le 1.11 )$

=> $P(| \= X- \mu| < 199 ) = P(Z \le 1.11 ) - P( Z \le -1.11 )$

From the z table the area under the normal curve to the left corresponding to 1.11 and -1.11 is

$P(Z \le 1.11 ) = 0.8665$

and

$P(Z \le - 1.11 ) = 0.1335$

$P(| \= X- \mu| < 199 ) = 0.8665 - 0.1335$

=> $P(| \= X- \mu| < 199 ) = 0.733$

8 0

3 years ago

PLEASE HELP :(( Which inequality is represented by the graph?

4vir4ik [10]

Answer:

y < 5/3x -3

Step-by-step explanation:

Used Desmos graphing calculator :)

4 0

4 years ago