Question

Does anyone know the answers to this? and please show work (I’ll mark you brainliest)

Answer 1

Answer:

8. A

First step is to distribute - to 6x and 3. Next u want to combine like terms. So 2x^2-6x^2 = -4x^2. Next 4x - 6x = -2x. Again 9 + 3 = 12. Combine and u get -4x ^2 - 2x +12

9. C

First you add 4x to both sides. Then you subtract 55 leaving -45 greater than or equal to 9x. Then you divide by nine and you get -5 is greater than or equal to x

10. B

First you distribute 5 so 15 -3x < -2x +6. Next add 2 to both sides. Then subtract 15 leaving -3x < -9. Least divide by -3 and you get x > 3(the sign was swapped bc dividing by a negative number means it has to)

11. B

For this you could just distribute the equations and we on that 7•4=28. And 7•5=35. I'm this case both of the numbers have to be negative so 7 has to be negative as well

12. C

Distribute -2/3 and you get 9q^2-2q+14/3+5q^2

Then combine like terms and 9q^2+5q^2=14q^2. Order them and ur answer is 14q^2-2q+14/3

Answer 2

Answer:

8) a.

9) c.

10) b.

11) b.

12) c.

Step-by-step explanation:

8.) 2x^2 + (4x-6x^2) + 9 - (6x+3)

Simplify: 4x^2 - 2x + 6

9.) -4x + 10 > 5x + 55

Subtract 10: -4x > 5x +45

Subtract 5x: -9x > 45

Divide by -9: x < -5

10.) 5(3 - x) < -2x + 6

Simplify: 15 - 5x < -2x + 6

Subtract 15: -5x < -2x - 9

Add 2x: -3x < -9

Divide by -3: x > 3

11.) -28x^2 + 35x

Divide by -7x: 4x - 5

Answer: -7x(4x - 5)

12.) 9q^2 - $\frac{2}{3}$(3q - 7) + 5q^2

Simplify: 14q^2 - 2q + $\frac{14}{3}$