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3 years ago

How do you write 283,980 in expanded form

Mathematics

2 answers:

Sindrei [870]3 years ago

7 0

200,000 + 80,000 + 3,000 + 900 + 80

kramer3 years ago

6 0

Enjoy
200,000 + 80,000 + 3,000 + 900 + 80

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in the equation dy+3x=2, for what value of d is the graph of the equation parallel to the graph of x-3y=0? the y axis?

IRISSAK [1]

Answer:

-9

Step-by-step explanation:

The slope of the the solving equation is triple the slope of the given equation. Therefore, the y coefficient must also be triple of the other y coefficient.

8 0

2 years ago

Step by set

Roman55 [17]

Answer:

2 2/3 or 8/3

Step-by-step explanation:

Step by step I am guessing? (Is that what each question is for?)

STEP 1

First we have to find 1/3 of 23:

23/3= 1/3 of 23

Then:

5/1 = 15/3

STEP 2

Subtract:

23-15= 8/3

8/3 or 2 2/3

3 0

3 years ago

M is between points C and Q. CM=17 and CQ=21. What is MQ?

katrin2010 [14]

Sometimes it helps to draw it out...

(17)
C_______M_________Q
|___________________|
21

therefore, CM + MQ = CQ
17 + MQ = 21
MQ = 21 - 17
MQ = 4 <===

8 0

3 years ago

Read 2 more answers

54 ÷ (−6)<br><br><br> A. 9<br><br> B. -9<br><br> C. -8

sp2606 [1]

Answer:

Option B, -9

Hope this helps!

6 0

3 years ago

(08.07 HC)

andreev551 [17]

Answer:

$\textsf{A)} \quad x=-2, \:\:x=\dfrac{5}{2}$

$\textsf{B)} \quad \left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)$

C) See attachment.

Step-by-step explanation:

Given function:

$f(x)=2x^2-x-10$

To factor a <u>quadratic</u> in the form $ax^2+bx+c$ <em> , </em>find two numbers that multiply to $ac$ and sum to $b$ :

$\implies ac=2 \cdot -10=-20$

$\implies b=-1$

Therefore, the two numbers are -5 and 4.

Rewrite $b$ as the sum of these two numbers:

$\implies f(x)=2x^2-5x+4x-10$

Factor the first two terms and the last two terms separately:

$\implies f(x)=x(2x-5)+2(2x-5)$

Factor out the common term (2x - 5):

$\implies f(x)=(x+2)(2x-5)$

The x-intercepts are when the curve crosses the x-axis, so when y = 0:

$\implies (x+2)(2x-5)=0$

Therefore:

$\implies (x+2)=0 \implies x=-2$

$\implies (2x-5)=0 \implies x=\dfrac{5}{2}$

So the x-intercepts are:

$x=-2, \:\:x=\dfrac{5}{2}$

The x-value of the vertex is:

$\implies x=\dfrac{-b}{2a}$

Therefore, the x-value of the vertex of the given function is:

$\implies x=\dfrac{-(-1)}{2(2)}=\dfrac{1}{4}$

To find the y-value of the vertex, substitute the found value of x into the function:

$\implies f\left(\dfrac{1}{4}\right)=2\left(\dfrac{1}{4}\right)^2-\left(\dfrac{1}{4}\right)-10=-\dfrac{81}{8}$

Therefore, the vertex of the function is:

$\left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)$

Plot the x-intercepts found in Part A.

Plot the vertex found in Part B.

As the <u>leading coefficient</u> of the function is positive, the parabola will open upwards. This is confirmed as the vertex is a minimum point.

The axis of symmetry is the <u>x-value</u> of the <u>vertex</u>. Draw a line at x = ¹/₄ and use this to ensure the drawing of the parabola is <u>symmetrical</u>.

Draw a upwards opening parabola that has a minimum point at the vertex and that passes through the x-intercepts (see attachment).

5 0

2 years ago