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elena-s [515]
3 years ago
15

Which set of equations is enough information to prove that lines a and b are parallel lines cut by transversal f? m∠4 = 110° and

m∠3 = 70° m∠1 = 110° and m∠2 = 110° m∠1 = 110° and m∠3 = 70° m∠2 = 110° and m∠3 = 110°

Mathematics
2 answers:
vlada-n [284]3 years ago
6 0

Answer:

m∠1 = 110° and m∠3 = 70°

Step-by-step explanation:

atroni [7]3 years ago
4 0

see the attached figure to better understand the problem

we know that

If a and b are parallel lines

then

m∠1=m∠4 --------> by alternate exterior angles

m∠3+m∠4=180\° --------> by supplementary angles

so

m∠3+m∠1=180\°

therefore

<u>the answer is the option</u>

m∠1 = 110° and m∠3 = 70°



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Step-by-step explanation:

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Required

Find the equivalent

We start by changing the / to *

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\frac{2a + 1}{10a - 5} * \frac{4a^2 - 1}{10a}

Factorize 10a - 5

\frac{2a + 1}{5(2a - 1)} * \frac{4a^2 - 1}{10a}

Expand 4a² - 1

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\frac{2a + 1}{5(2a - 1)} * \frac{(2a)^2 - 1^2}{10a}

Express (2a)² - 1² as a difference of two squares

Difference of two squares is such that: a^2- b^2= (a+b)(a-b)

The expression becomes

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Combine both fractions to form a single fraction

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Divide the numerator and denominator by 2a - 1

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Simplify the numerator

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\frac{(2a + 1)^2}{50a}

Hence,

\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1} = \frac{(2a + 1)^2}{50a}

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