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mihalych1998 [28]
3 years ago
5

Is this is the right answers

Mathematics
2 answers:
Hatshy [7]3 years ago
7 0

Answer:

Yes your answer is correct! You solved it the proper way.

Kamila [148]3 years ago
5 0
That’s correct good job but, there are other ways to do it!!
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11 less than a number is more than seventeen
Tasya [4]
17∠x-11 set up the equation like this
28∠x      add 17 to the other side, and you get x is greater than 28
3 0
3 years ago
MODELING REAL LIFE There are a total of 64 students in a filmmaking club and a yearbook club. The filmmaking club has 14 more st
VashaNatasha [74]

Answer:

The system of linear equations is x + y = 64 and x = y + 14.

Given that,

The total number of students is 64 .

Here we assume the x be the number of students in filmmaking club .

And, y be the number of students in yearbook club.

Based on the above information, the calculation is as follows:

x + y = 64

And,

x = y + 14

Therefore,

We can say that

Number of students in yearbook club = 25

And, the number of students in filmmaking club = 39

3 0
2 years ago
Find an equation in slope-intercept form for the line with slope -12 and y-intercept = 1/2
Kruka [31]
M = -12
point = (0, 1/2)

Find the slope-intercept equation
y - y₁ = m(x - x₁)
y - 1/2 = -12 (x - 0)
y - 1/2 = -12x
y = -12x + 1/2
4 0
3 years ago
Can someone help me ASAP
Vlad [161]

X=10 that how u would get the 12 and the 2

3 0
3 years ago
An instructor who taught two sections of Math 161A, the first with 20 students and the second with 30 students, gave a midterm e
uranmaximum [27]

Answer:

<em>The answers are for option (a) 0.2070  (b)0.3798  (c) 0.3938 </em>

Step-by-step explanation:

<em>Given:</em>

<em>Here Section 1 students = 20 </em>

<em> Section 2 students = 30 </em>

<em> Here there are 15 graded exam papers. </em>

<em> (a )Here Pr(10 are from second section) = ²⁰C₅ * ³⁰C₁₀/⁵⁰C₁₅= 0.2070 </em>

<em> (b) Here if x is the number of students copies of section 2 out of 15 exam papers. </em>

<em>  here the distribution is hyper-geometric one, where N = 50, K = 30 ; n = 15 </em>

<em>Then, </em>

<em> Pr( x ≥ 10 ; 15; 30 ; 50) = 0.3798 </em>

<em> (c) Here we have to find that at least 10 are from the same section that means if x ≥ 10 (at least 10 from section B) or x ≤ 5 (at least 10 from section 1) </em>

<em> so, </em>

<em> Pr(at least 10 of these are from the same section) = Pr(x ≤ 5 or x ≥ 10 ; 15 ; 30 ; 50) = Pr(x ≤ 5 ; 15 ; 30 ; 50) + Pr(x ≥ 10 ; 15 ; 30 ; 50) = 0.0140 + 0.3798 = 0.3938 </em>

<em> Note : Here the given distribution is Hyper-geometric distribution </em>

<em> where f(x) = kCₓ)(N-K)C(n-x)/ NCK in that way all these above values can be calculated.</em>

7 0
3 years ago
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