Answer:
Hence, the coordinates of pre-image are:
A(1,6) , B(0,4) , C(3,4) , D(2,6)
Step-by-step explanation:
We have to find the coordinates of the vertices of the pre-image given?
Ry= −x ◦ T_1, −2(x, y)
i.e. we have to find the composition of reflection along the line y=-x and translation with the rule:
(x,y) → (x+1,y-2)
Now we have coordinates of A",B",C" and D" as:
A"(-4,-2)
B"(-2,-1)
C"(-2,-4)
D"(-4,-3)
Now we are asked to find the coordinates of the pre-image.
Also when any point is reflected along y=-x then the point is transformed to:
(x,y) → (-y,-x)
Let A,B,C and D are the points of the pre-image.
Hence, the coordinates of the pre-image are given as:
so, the transformation is given as:
A→A'→A"
B→B'→B"
C→C'→C"
D→D'→D"
Where A',B',C',D' represents the transformation after translation and A",B",C",D" represents the transformation after reflection as well.
The coordinates of A' are (2,4)
B' are (1,2)
C' are (4,2)
and D' are (3,4)
Now, the coordinates of pre-image are given as:
A'(x,y) → A(x-1,y+2)=A(1,6)
B'(x,y) → B(x-1,y+2)=B(0,4)
C'(x,y) → C(x-1,y+2)=C(3,4)
and D'(x,y) → D(x-1,y+2)=D(2,6)
Hence, the coordinates of pre-image are:
A(1,6) , B(0,4) , C(3,4) , D(2,6)
