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Juli2301 [7.4K]
3 years ago
5

Random assortment of maternal and paternal chromosomes along the spindle during meiosis generates A. gametes that contain some p

aternal and some maternal chromosomes. B. gametes that contain only paternal or maternal chromosomes. C. gametes that contain extra chromosomes.
Biology
1 answer:
Harlamova29_29 [7]3 years ago
7 0

Answer:

B: gametes that contain only paternal or maternal chromosome

Explanation:

During meiosis, homologous chromosome separates and sister chromatids move to opposite poles as a result of the shortening of the spindle. Since maternal and paternal chromosomes will independent separate during meiosis, this will result in the formation of gametes with either paternal or maternal chromosome and never a mixture of the two.

Paternal chromosomes will assort to give paternal gametes

Maternal chromosomes will assort to give maternal gametes

<em>The correct option is B. The assortment will leads to formation of gametes that contain only paternal or maternal chromosomes</em>

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Explanation:

Sorry to ask the two questions, I asked why the two options are in the process:Reduction. In the second stage, ATP and NADPH are used to convert the 3-PGA molecules into three-carbon sugar molecules, glyceraldehyde-3-phosphate ( G3P ). At this stage, it gets its name because NADPH donates, or reduces , electrons to a three-carbon intermediate to form G3P.[Ocultar detalhes]

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Simplified diagram of the reduction step of the Calvin cycle showing the carbon atoms, but not the complete molecular structures. A 3-PGA molecule first receives a second phosphate group from ATP (generating ADP). Then, the doubly phosphorylated molecule receives electrons from NADPH and is reduced to form glyceraldehyde-3-phosphate. This reaction generates NADP + and also releases an inorganic phosphate.

First, each 3-PGA molecule receives a phosphate group from ATP, becoming a doubly phosphorylated molecule called 1,3-bisphosphoglyceride (and leaving an ADP as a by-product).

Second, 1,3-bisphosphoglycerate molecules are reduced (gain electrons). Each molecule receives two electrons from NADPH and loses one of its phosphate groups, becoming a three-carbon sugar called glyceraldehyde-3-phosphate (G3P) . This step produces NADP^+

+

start superscript, plus, end superscript and phosphate (\text P_iP

i

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The chemical structures and real reactions are:

Reactions of the Calvin cycle reduction step, showing the molecular structures of the molecules involved.

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