3 years ago

Given ΔADC and ΔAEB, What is AE?

Mathematics

1 answer:

AysviL [449]3 years ago

5 0

Answer:

As shown in picture,

EB is perpendicular with AC

DC is perpendicular with AC

=> EB // DC

Applying Thales theorem:

BC/AC = ED/AD

=> AD = ED x AC/BC = 72 x 88/55 = 115.2

=> AE = AD - ED = 115.2 - 72 = 43.2

Hope this helps!

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