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S_A_V [24]
3 years ago
9

Can you please help me with this I will crown you brainly

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
7 0
C. ΔKPT ≈ ΔKRT

It's identical on both sides. 
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What is the area of the composite figure whose vertices have the following coordinates?
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Area of the composite figure: A=?

A=A1+A2

Area of the parallelogram: A1
Area of the triangle: A2

A1=b*h1
b=2-(-4)=2+4→b=6 or
b=4-(-2)=4+2→b=6
h1=3-(-1)=3+1→h1=4

A1=b*h1=6*4→A1=24

A2=b*h2/2
h2=-1-(-3)=-1+3→h2=2
A2=6*2/2→A2=6

A=A1+A2
A=24+6
A=30

Answer: The area of the composite figure is 30 <span>units²</span>
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Step-by-step explanation:

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