Ask question

Ask question

All categories

3 years ago

11

What is 204 thousands

1 answer:

max2010maxim [7]3 years ago

8 0

204 thousands equals to 204, 000 as the mathematical value and expression.

In expanded form
200, 000 + 4, 000 = 204, 000

In word form,
Two hundred and four thousand

You might be interested in

At an ice cream store, $20 is enough to buy 5 cones and 5 sundaes. or, $20 can buy 4 sundaes, 6 cones and there would be 80 cent

satela [25.4K]

There will not be 80 cents left over

3 0

4 years ago

select the correct answer. and the figure, angle k measures 45°. what is the measurement of angle c? 38° 45° 90° 98°.

LuckyWell [14K]

From the figure, we can conclude that the little triangle is an isosceles triangle, the greatest angle is 90 because ∠A = 90 and they are supplementary, therefore, using the triangle sum theorem:

$\begin{gathered} m\angle J=m\angle K \\ m\angle K+m\angle K+90=180 \\ 2m\angle K=180-90 \\ 2m\angle K=90 \\ m\angle K=\frac{90}{2} \\ m\angle K=45 \end{gathered}$

8 0

1 year ago

Steven paid $10,000 in interest on a 5 year loan on $10,000. What was the interest rate he paid on the loan?

serg [7]

Answer:

I think steven paid 50,000 dollars in total

Step-by-step explanation:

8 0

4 years ago

-2.2 + (-3.7 +(-1.4) =(-2-2 + (-3. 7) + (-1.4)<br>+ (-2:24<br>S1-3

Luda [366]

6 because it has donuts

5 0

3 years ago

A rectangular piece of land borders a wall. The land is to be enclosed and to be into divided 3 equal plots with 200 feet of fen

baherus [9]

Answer:

Area = 2500 square feet is the largest area enclosed

Step-by-step explanation:

A rectangular piece of land borders a wall. The land is to be enclosed and to be into divided 3 equal plots with 200 feet of fencing

Let x be the length of each box and y be the width of the box

Perimeter of the box= 3(length ) + 4(width)

$200=3x+4y$

solve for y

$200=3x+4y$

$200-3x=4y$

divide both sides by 4

$y=50-\frac{3x}{4}$

Area of the rectangle = length times width

$Area = 3x \cdot y$

$Area = 3x \cdot (50-\frac{3x}{4})$

$A=150x-\frac{9x^2}{4}$

Now take derivative

$A'=150-\frac{9x}{2}$

Set it =0 and solve for x

$0=150-\frac{9x}{2}$

$150=\frac{9x}{2}$

multiply both sides by 2/9

$x=\frac{100}{3}$

$A''=-\frac{9}{2}$

For any value of x, second derivative is negative

So maximum at x= 100/3

$A=150x-\frac{9x^2}{4}$ , replace the value of x

$A=150(\frac{100}{3})-\frac{9(\frac{100}{3})^2}{4})$

Area = 2500 square feet is the largest area enclosed

3 0

3 years ago