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nadezda [96]
3 years ago
12

A process manufactures ball bearings with diameters that are normally distributed with mean 25.1 millimeters and standard deviat

ion 0.08 millimeter. (a) [5pts] What proportions of the diameters are greater than 25.4
Mathematics
1 answer:
Katena32 [7]3 years ago
7 0

Answer:

The  proportions of the diameters that are greater than 25.4 millimeters is 5%.

Step-by-step explanation:

Given;

mean of the normal distribution, m = 25.1 millimeters

standard deviation, d = 0.08 millimeter

1 standard deviation above the mean = m + d = 25.1 + 0.08 = 25.18

2 standard deviation above mean =  m + 2d = 25.1 + 2(0.08) = 25.26

3 standard deviation above the mean = m + 3d = 25.1 + 3(0.08) = 25.34

4 standard deviation above the mean = m + 4d = 25.1 + 4(0.08) = 25.42

To obtain a diameter greater than 25.4, we select data after 4 standard deviation above the mean.

Data within 4 standard deviation above the mean is 95%

Data outside 4 standard deviation above the mean is 5%

Therefore, the  proportions of the diameters that are greater than 25.4 millimeters is 5%.

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Less than 3 is about 10.75% and greater than 13 is about 6.18%.

To find these percents, you need to find the z-score for each value. Then, use your table to find the correct percent. Be sure to find the side above 13 when you use your chart.

For less than 3:
(3 - 7.45) / 3.6 = -1.24 = The percent below this is 0.1075

For greater than 13:
(13 - 7.45) / 3.6 = 1.54 = The percent above this is 0.0618
7 0
3 years ago
Let the equation of a line be described by Equation A:
umka2103 [35]
10y - 5x = 40   Add 5x to both sides
       10y = 5x + 40   Divide both sides by 10
          y = \frac{1}{2}x + 4

The y-intercept is 4 and the slope of the line is \frac{1}{2}.

You can find these by comparing your equation to the equation y = mx + b, where m is the slope of the line and b is the y-intercept.
4 0
3 years ago
Ingrid dug a trench 18/20 of a meter long. The next day she dug 9/20 of a meter more of the trench. What is a reasonable estimat
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3 years ago
Which statement is correct?
Digiron [165]
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4 0
3 years ago
What are the solutions of the quadratic equation 0 = 4(x - 3)2 - 16?
erastovalidia [21]

Answer:

 x = 5, x = 1

Step-by-step explanation:

The quadratic equation 0 = 4(x - 3)2 - 16.

Using binomial theorem, (a - b)2 = a2 - 2ab + b2 to expand (x - 3)2.

0 = 4(x2 - 6x + 9 ) - 16.

Using distributive property to multiply 4 by x2 - 6x + 9.

0 = 4x2 - 24x + 36 - 16.

Subtract 16 from 36 to get 20.

0 = 4x2 - 24x + 20.

4x2 - 24x + 20 = 0.

Divide both sides by 4.

x2 - 6x + 5 = 0.

To solve the equation, factor and rewrite as x2 + ax + bx + 5

a + b = -6, ab = 1(5) = 5.

a = -5, b = -1.

Rewriting x2 - 6x + 5 as

(x2 - 5x) + (-x + 5)

Factor x in the first and -1 in the second group.

x(x - 5) - (x - 5)

Factor out common term

(x - 5)(x - 1)

By solving the above, we get

x = 5, x = 1

8 0
2 years ago
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