According to the identity if a+b+c=0
then a3+b3+c3=3abc
a3+b3+c3/abc=3
a2*a/bc*a+b2*b/ca*b+c2*c/ab*c=3
cancel a,b,c in all the fraction then you get
<span>a²/bc+b²/ca+c²/ab=3.
</span>hence proved
I can’t find the answer. Are you sure this is the whole question?
- 1 1/10 + (-1 2/5)
- 1 1/10 + (-1 4/5)
-2 5/10
-2 1/2
