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Vsevolod [243]
3 years ago
8

Two functions are combined resulting in the function j(x) = –3x2 + 5.

Mathematics
1 answer:
labwork [276]3 years ago
7 0

Answer:

two quadratic functions combined by addition

a linear function and a quadratic function combined by addition

two linear functions combined by multiplication

Step-by-step explanation:

-3x² + 5

(-4x² + 4) + (x² + 1)

-3x² + 5

(-3x² - x) + (x + 5)

-3x² + 5

(sqrt(5) - sqrt(3)x)(sqrt(5) + sqrt(3)x)

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A family has two cars. The first car has a fuel efficiency of 35 miles per gallon of gas and the second has a fuel efficiency of
cestrela7 [59]

The amount of gas consumed by first and second car were 20 gallons and 15 gallons respectively.

<em><u>Explanation</u></em>

Suppose,  x gallons of gas were consumed by the first car.

As the total gas consumption in one week is 35 gallons, so the amount of gas consumed by second car will be:  (35-x) gallons.

The first car has a fuel efficiency of 35 miles per gallon of gas and the second has a fuel efficiency of 15 miles per gallon of gas.

So, the <u>distance traveled by the first car</u> in x gallons of gas =35x miles and the <u>distance traveled by the second car</u> in (35-x) gallons of gas =15(35-x) miles.

Given that, the two cars went a <u>combined total of 925 miles</u>. So, the equation will be.....

35x+15(35-x)=925\\ \\ 35x+525-15x=925\\ \\ 20x=925-525=400\\ \\ x=\frac{400}{20}=20

So, the amount of gas consumed by the first car is 20 gallons and the amount of gas consumed by the second car is: (35 - 20) = 15 gallons.

3 0
4 years ago
Consider the sequence 10, 2..
romanna [79]

Answer:  see below

<u>Step-by-step explanation:</u>

1) 10, 2, 1.2, 1.12, 1.112, 1.1112

t_n=\dfrac{t_{n-1}}{10}+1

t₁ = 10

t₂ = 10/10 + 1    = 2

t₃ = 2/10 + 1     = 1.2

t₄ = 1.2/10 + 1   = 1.12

t₅ = 1.12/10 + 1  = 1.112

t₆ = 1.112/10 + 1 = 1.1112

2)  10, 2, -2, -4, -5, -5.5, ...

t_n=\dfrac{t_{n-1}}{2}-3

t₁ = 10

t₂ = 10/2 - 3 =   2

t₃ = 2/2 - 3  =  -2

t₄ = -2/2 - 3 =  -4

t₅ = -4/2 - 3 =  -5

t₆ = -5/2 - 3 = -5.5

8 0
3 years ago
4.
NemiM [27]

Answer:

i belive the answer is B

Step-by-step explanation:

6 0
3 years ago
If $x$ is the average of $13$, $-16$, and $6$ and if $y$ is the cube root of $8$, find $x^2 + y^3$. Please Help
Alekssandra [29.7K]

Answer:

If we have a set of N elements:

{x₁, x₂, ..., xₙ}

The mean value (also called the average value) Is calculated as:

Average = (x₁ + x₂ + ... + xₙ)/n

So if x is the average of 13, -16 and 6 ( a total of 3 values)

x will be equal to:

x = (13 + (-16) + 6)/3 = (19 - 16)/3 = 3/3 = 1

x = 1

And we know that:

y = ∛8

Remember that:

2*2 = 4

and

4*2 = 8

then

2*2*2 = 2^3 = 8

then ∛8 = 2.

So we have:

y = ∛8 = 2

Now we can replace these values in the equation:

x^2 + y^3

replacing:

x = 1

y = 2

we get:

1^2 + 2^3 = 1 + 8 = 9

5 0
3 years ago
What is the answer for cos(43) = sin(?)
oee [108]

Answer:

Step-by-step explanation:

cos 43=cos (90-47)=sin 47

6 0
3 years ago
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