All categories

3 years ago

(7x+3)(x-9) need help

1 answer:

8 0

7x^2-63x+3x-27=0

Simplify.

7x^2-60x-27=0

To find value of x, 7x+3=0
x-9=0

x1=-3/7
x2=9

Substitute back in equation to find the answer either x1 or x2

You might be interested in

(4, -2), y = –2x + 3 PLS HELP HOW DO I DO THIS?

Alex787 [66]

It looks like your instructor wants you to write in point-slope form.

the equation for point slope form is quite simple

y-y1=m(x-x1)

your variables:

y and x: just state these as they are

m: slope

y1 and x1: the numbers in the point given

keep in mind a double negative equals a positive, so when you come across a negative coordinate you would put + instead of - in your equation.

your final answer would be

y+2=-2(x-4)

I hope this helped :)

please don't hesitate to ask if you have any more questions

3 0

2 years ago

Some one please help with any of these!!!!

lidiya [134]

11.) y=(4/5)x-(12/5)

8 0

3 years ago

-5x-2y= −5x−2y= \,\,-40 −40 y= y= \,\,2x+2 2x+2

Eva8 [605]

Answer: look at the ss :))

Step-by-step explanation:

4 0

2 years ago

Select the number and name of the terms below (select 2): 2121

mihalych1998 [28]

Its a monomial and it has 4 terms

6 0

3 years ago

Let L be the line parametrized by x = 2 + 2t, y = 3t, z = −1 − t. (a) Find a linear equation for the plane that is perpendicular

Elden [556K]

Answer:

Step-by-step explanation:

Given that L is a line parametrized by

$x = 2 + 2t, y = 3t, z = −1 − t$

The plane perpendicular to the line will have normal as this line and hence direction ratios of normal would be coefficient of t in x,y,z

i.e. (2,3,-1)

So equation of the plane would be of the form

$2x+3y-z =K$

Use the fact that the plane passes through (2,0,-1) and hence this point will satisfy this equation.

$2(2)+3(0)-(-1) =K\\K =5$

So equation is

$2x+3y-z =5$

b) Substitute general point of L in the plane to find the intersecting point

$2(2+2t)+3t-(-1-t) =5\\4+8t+1=5\\8t=0\\t=0\\(x,y,z) = (2,0,-1)$

i.e. same point given.

3 0

3 years ago