Answer:
2022
Step-by-step explanation:
2 + 4x = y
y = 2 + 4(505)
y = 2 + 2020
y = 2022
Answer: (0,-1) and (1/3,0)
Step-by-step explanation:
Answer:
12a^2 - 9a + 5
Step-by-step explanation:
(5a^2 - 6a - 4) - (-7a^2 + 3a - 9)
5a^2 + 7a^2 = 12a^2
-6a - 3a = -9a
-4 + 9 = 5
12a^2 - 9a + 5
6.5c + 9.7a = 1721.4
a = 4c
6.5c + 9.7(4c) = 1721.4
6.5c + 38.8c = 1721.4
45.3c = 1721.4
c = 1721.4 / 45.3
c = 38...so there were 38 childrens' tickets <==
and 152 adult tickets
Answer:
51,111%
Step-by-step explanation:
We know that 45% have a dog but no cat. While 23% have both a dog and a cat.
Then Pr(X has cat|X has dog) = Pr(X has dog and cat)/Pr(X has dog)
= Pr(X has dog and cat)/Pr(X has dog) = 0.23/0.45 = 0.51 ≈ 51,111%
The probability that a student’s family owns a cat if the family owns a dog is 51,111%