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Virty [35]
3 years ago
12

If the diagonals of a quadrilateral divide each other proportionally then it is a​

Mathematics
1 answer:
Artist 52 [7]3 years ago
3 0

Answer:

Step-by-step explanation:

trapezium

<h2>If the diagonals of a quadrilateral divide each other proportionally, then prove that the quadrilateral is a trapezium.</h2>
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Write 2.5896 X 10° in standard notation.
Blababa [14]

Answer:

2.5896

Explanation:

Zero power rule: The zero exponent rule states that any number raised to a power of zero equals one.

10^0 is 1, so nothing changes

8 0
3 years ago
Which of the following is a Geometric Series?
Katarina [22]

I dont know the answer

Step-by-step explanation:

little girl I am sorry

8 0
3 years ago
Given vectors u = (−1, 2, 3) and v = (3, 4, 2) in R 3 , consider the linear span: Span{u, v} := {αu + βv: α, β ∈ R}. Are the vec
julia-pushkina [17]

Answer:

(2,6,6) \not \in \text{Span}(u,v)

(-9,-2,5)\in \text{Span}(u,v)

Step-by-step explanation:

Let b=(b_1,b_2,b_3) \in \mathbb{R}^3. We have that b\in \text{Span}\{u,v\} if and only if we can find scalars \alpha,\beta \in \mathbb{R} such that \alpha u + \beta v = b. This can be translated to the following equations:

1. -\alpha + 3 \beta = b_1

2.2\alpha+4 \beta = b_2

3. 3 \alpha +2 \beta = b_3

Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for \alpha,\beta and check if the third equationd is fulfilled.

Case (2,6,6)

Using equations 1 and 2 we get

-\alpha + 3 \beta = 2

2\alpha+4 \beta = 6

whose unique solutions are \alpha =1 = \beta, but note that for this values, the third equation doesn't hold (3+2 = 5 \neq 6). So this vector is not in the generated space of u and v.

Case (-9,-2,5)

Using equations 1 and 2 we get

-\alpha + 3 \beta = -9

2\alpha+4 \beta = -2

whose unique solutions are \alpha=3, \beta=-2. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.

4 0
3 years ago
The length of the rectangular basketball court is 44 feet more than the width. If the perimeter of the basketball court is 288 f
Temka [501]
Let's first say that L=W+44

and then remember that perimeter is P=2L+2W

replace the L with W+44

we then get P=2(W+44)+2W, now I'll solve it

P=2W+88+2W
P=4W+88

substitute 288 for P

288=4W+88
200=4W
50=W

so now we now how wide the court is. add 44 to find the length which gives you L=94

as always plug the numbers back into your perimeter equation to ensure L and W are correct
8 0
3 years ago
I need to know how to round to the nearest hundredth in the number 1.120
ryzh [129]
You can either round to 1000 or 2000 but 1.120 is closer to 1000
8 0
3 years ago
Read 2 more answers
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