Question

3} x - 2 = {4}^{2} " alt=" \sqrt{3} x - 2 = {4}^{2} " align="absmiddle" class="latex-formula">
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Answer 1

Answer:

$x=6\times\sqrt{3}$

Step-by-step explanation:

Given:

$\sqrt{3}x -2=4^{2}$

To Find:

x =?

Solution:

We have,

$\sqrt{3}x -2=4^{2}\\\\\sqrt{3}x -2=16\\\\\sqrt{3}x=16+2\\\\\sqrt{3}x =18\\\\x=\frac{18}{\sqrt{3} }$

As square root of 3 is in denominator we will rationalize the denominator i.e multiply and divide by square root 3,so we get

$\therefore x = \frac{18}{\sqrt{3} }\times \frac{\sqrt{3} }{\sqrt{3} } \\ \\\therefore x=\frac{18}{3}\times \sqrt{3}\\\\\therefore x=6\sqrt{3}$

∴ x = 6√3 is the final answer.