9514 1404 393
Answer:
more than 10 months
Step-by-step explanation:
Alex's balance starts at 720 and increases by 80 each month. It can be represented by ...
A = 720 +80m
Jax's balance starts at 480 and increases by 120 each month. It can be represented by ...
J = 480 +120m
Jax's balance will be more than 160 more than Alex's when ...
J -A > 160
(480 +120m) -(720 +80m) > 160
40m -240 > 160 . . . . . . . . . . . . . collect terms
m -6 > 4 . . . . . . . . . . . . . . . divide by 40
m > 10 . . . . . . . . . . . . add 6
It will take more than 10 months for Jax to have saved over $160 more than Alex.
Answer:
Not if store closes at 5pm. The time store closes isn’t mentioned.
Step-by-step explanation:
If it takes her 35 minutes to drive to the hardware store, she would arrive at 5:05 (4:30+:35 minutes)
We can calculate this using arc length formula.
![L= \int\limits^a_b { \sqrt[]{1+ (\frac{dy}{dx} } )^2} \, dx](https://tex.z-dn.net/?f=L%3D%20%5Cint%5Climits%5Ea_b%20%7B%20%5Csqrt%5B%5D%7B1%2B%20%28%5Cfrac%7Bdy%7D%7Bdx%7D%20%7D%20%29%5E2%7D%20%5C%2C%20dx%20)
The first step is to find the derivative of the given function.


Now we plug this back into original integral.
![L= \int\limits^a_b { \sqrt[]{1+ 9x} \, dx](https://tex.z-dn.net/?f=L%3D%20%5Cint%5Climits%5Ea_b%20%7B%20%5Csqrt%5B%5D%7B1%2B%209x%7D%20%5C%2C%20dx%20)
We solve this integral using substituition u=9x+1. This way we end up solving elementary integral.
A final solution is:

Finaly we get that arc lenght is:
Answer:
f[g(1)]=6.
Explanation:
Given f(n) and g(n) defined below:

First, we evaluate g(1):

Therefore:

Therefore, f[g(1)]=6.
Let x be the number of adult tickets and y be the number of student tickets.
From the first sentence we can set up both equations:
1) x + y = 48
2) 7x + 3y = 220
Rearrange #1 to isolate x:
x = 48 - y
Sub that into #2 and solve for y to get your answer:
7(48 - y) + 3y = 220
336 - 7y + 3y = 220
-4y = -116
y = 29
29 student tickets were sold.