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3 years ago

Use the formula d=rt to find the value of the missing variable.

Mathematics

1 answer:

Alexus [3.1K]3 years ago

5 0

D = rt
/t /t

D/t = r
80/16 = r
5 = r

Therefore r = 5ft/second

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Jacob receives $15 per week for his allowance. His parents have asked him to put $5 in his savings account and the rest of his a

drek231 [11]

Answer:

5:10

Step-by-step explanation:

$5-money he saves

$10-money he can spend

8 0

3 years ago

What system shows the correct numbers to multiply by the coefficients in order to eliminate y from the first two

Ann [662]

Answer:

3 (5x+2y = 0)

2 (2x – 3y = -19)

Step-by-step explanation:

5x+2y=0 (1)

2x-3y=-19 (2)

To eliminate y from the first two equation when applying the linear combination method

We will multiply y Equation (1) and (2) with 3 and 2 respectively so that the coefficients of y in the two equations +6 and -6 respectively

3(5x+2y=0)

2(2x-3y=-19)

We have,

15x+6y=0 (3)

4x-6y= -38 (4)

Add Equation (3) and (4)

19x=-38

x= -2

Substitute x= -2 into (1)

5x+2y=0

5(-2)+2y=0

-10+2y=0

-10= -2y

y=-10/-2

y=5, x=-2

3 0

3 years ago

The equation r(t)= (2t)i + (2t-16t^2)j is the position of a particle in space at time t. Find the angle between the velocity and

ankoles [38]

Answer:

The answer is 135 degrees.

Step-by-step explanation:

As we are given the position. If we take the <u>derivative</u>, we get the velocity vector. If we take the <u>derivative</u> again, we find the acceleration vector of the particle.

$r(t)=(2t)i+(2t-16t^{2})j$

$V(t)=2i+(2-32t)j$

$a(t)=-32j$

At time t=0;

$v(t)=2i+2j$

$a(t)=-32j$

As i attach in the picture the angle between the velocity and acceleration vector is $(45+90)=135$ degrees

4 0

3 years ago

Factorize 2a^2+7a-15

loris [4]

$\huge\bf \pink {\underline{Solution :-}}$

$2 {a}^{2} + 7a - 15$

$= 2 {a}^{2} + 10a - 3a - 15$

$= 2a(a + 5) - 3(a + 5)$

$= (a + 5)(2a - 3)$

$\sf \red{Hence, Answer \: is \: (a + 5)(2a - 3).}$

$\\$

$\bf \purple{ \underline{ Important \: Formulas \: for \: Factorization :-}}$

$• \: {a}^{2} + 2ab + {b}^{2} = {(a + b)}^{2}$

$• \: (a + b)(a - b) = {a}^{2} - {b}^{2}$

$• \: {a}^{2} - 2 ab + {b}^{2} = {(a - b)}^{2}$

$• \: {a}^{3} + 3 {a}^{2} b + 3a {b}^{2} + {b}^{3} = {(a + b)}^{3}$

$• \: {a}^{3} - 3 {a}^{2} b + 3a {b}^{2} - {b}^{3} = {(a - b)}^{3}$

$• \: {(a + b)}^{2} + {(a - b)}^{2} = 2( {a}^{2} + {b}^{2} )$

$• \: {(a + b)}^{2} - {(a - b)}^{2} = 4ab$

$• \: (a + b)( {a}^{2} -ab + {b}^{2} ) = {a}^{3} + {b}^{3}$

$• \: (a - b)( {a}^{2} + ab + {b}^{2} ) = {a}^{3} - {b}^{3}$

$• \: {( \frac{a + b}{2} )}^{2} - ( {\frac{a - b}{2} } )^{2} = ab$

5 0

3 years ago

Read 2 more answers

I NEED HELP ASAP!!!!!!!!

geniusboy [140]

Answer: b

Step-by-step explanation:

7 0

3 years ago