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IrinaK [193]
3 years ago
11

cout << "Part 1" << endl; // Part 1 // Enter the statement to print the numbers in index 4 and index 9 // put a spac

e in between the two numbers cout << endl; // Enter the statement to print the numbers 3 and 80 from the array above // put a space in between the two numbers cout << endl; // Enter the statement to change the number 1 in the array to be 12 // then write the statement to print out that number in the array cout << "\nPart 2" << endl; // Part 2 // Write a function called printAll. It takes in an array // and an integer that has the number of values in the array. // The function should print all the numbers in the array with // a space between each one. // Call the function on the line below. cout << "\nPart 3" << endl; // Part 3 // Write a function called printEven. It takes in an array and // an integer that has the number of values in the array. It prints // all the even numbers in the array with a space between each one. // This function returns the count of evens. int evens; // Call the function you just wrote and store the // answer in the variable evens declared above.
Computers and Technology
1 answer:
Margarita [4]3 years ago
3 0

Answer and Explanation:

#include <iostream>

using namespace std;

int printEven(int array[],int n)

{

int count=0;

for(int i=0;i<n;i++)

{

if(array[i]%2==0)

{

count++;

cout<<array[i]<<" ";

}

}

return count;

}

void printAll(int array[],int n)

{

for(int i=0;i<n;i++)

{

cout<<array[i]<<" ";

}

}

int computeTotalOdds(int array[],int n)

{

int count=0;

for(int i=0;i<n;i++)

{

if(array[i]%2!=0)

{

count++;

 

}

}

return count;

}

int main()

{

int array1[20] = {3, 18, 1, 25, 4, 7, 30, 9, 80, 16, 17};

int numElements = 11;

cout << "Part 1" << endl;

cout<<array1[4]<<" "<<array1[9];

cout << endl;

cout<<array1[0]<<" "<<array1[8];

cout << endl;

array1[2]=12;

cout << "\nPart 2" << endl;

printAll(array1,numElements);

 

cout << "\nPart 3" << endl;

int evens;

evens=printEven(array1,numElements);

 

 

 

 

// This will print the number of evens in the array.

cout << endl << evens;

 

cout << "\nPart 4" << endl;

 

int total;

 

total=computeTotalOdds(array1,numElements);

cout << endl << total;

 

return 0;

}

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Grace [21]

Answer:

yes go to settings then apps

Explanation:

that's how I did mines

8 0
2 years ago
Consider a set of mobile computing clients in a certain town who each
poizon [28]

Answer: answer given in the explanation

Explanation:

We have n clients and k-base stations, say each client has to be connected to a base station that is located at a distance say 'r'. now the base stations doesn't have allocation for more than L clients.

To begin, let us produce a network which consists of edges and vertex

Network (N) = (V,E)

where V = [S, cl-l, - - - -  cl-n, bs-l - - - - - - bs-k, t]

given that cl-l, - - - - - cl-n represents nodes for the clients

also we have that bs-l, - - - - - bs-k represents the nodes for base station

Also

E = [ (s, cl-i), (cl-i,bs-j), (bs-j,t)]

(s, cl-i) = have capacity for all cl-i (clients)

(cl-i,bs-j) = have capacity for all cl-i  clients & bs-j (stations)

⇒ using Fond Fulkorson algorithm we  find the max flow in N

⇒ connecting cl-i clients to  bs-j stations

      like (cl-i, bs-j) = 1

   if f(cl-i, bs-j)  = 0

⇒ say any connection were to produce a valid flow, then

if cl-i (clients) connected                f(s,cl-i) = 1 (o otherwise)

if cl-i (clients) connected  to bs-j(stations)   f(cl-i,bs-j) = 1 (o otherwise)

   f(bs-j,t) = no of clients  (cl-i)  connected to bs-j

⇒ on each node, the max flow value (f) is longer than the no of clients that can be connected.

⇒ create the connection between the client and base station i.e. cl-l to base bs-j iff    f(cl-i, bs-j) = 1

⇒ when considering the capacity, we see that any client cannot directly connect to the base stations, and also the base stations cannot handle more than L clients, that is because the load allocated to the base statsion is L.

from this, we say f is the max no of clients (cl-i) that can be connected if we find the max flow, we can thus connect the client to the base stations easily.

cheers i hope this helps

5 0
3 years ago
The ____ line for any e-mail messages you write should clearly state the intention of the e-mail..
KatRina [158]

The <u>subject </u>line for any e-mail messages you write should clearly state the intention of the e-mail.

Electronic mail (e-mail) is a method of digital communications in which messages are exchanged through the internet. The messages are sent from a sender to one or more receivers.  Depending on user’s perspective, every user uses e-mail differently.  Communicating via e-mail requires e-mail platforms such as G*mail, Ya*hoo! Mail, Hot*mail, and Out*look etc. In the every e-mail, there is a subject line that clearly state the intention of the e-mail.

Subject line is an important element of an e-mail. Through the subject line, the message written in the e-mail is briefly summarized in six to eight words. A clearly written subject line provides the recipient a clear understanding that why the email has been sent. When recipient replies back to the e-mail, the subject line is changed accordingly.

This is the subject line of the e-mail that convince the receiver whether to open and read the e-mail. So, it should be written in the way that gives clear intention of the e-mail. We can say that the subject line of the e-mail is the most significant few words in the whole e-mail to convey the main purpose of the e-mail.

You can learn more about subject line at

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3 0
1 year ago
Assume you are using the text's array-based queue and have just instantiated a queue of capacity 10. You enqueue 5 elements and
ASHA 777 [7]

The indices of the internal array elements that hold the remaining elements is c) 2 to 4

<h3>Calculations and Parameters:</h3>

For us to create a capacity of 10 for the queue, we would enqueue:

We would create a queue of capacity 10:

<h3>Queue q(10);</h3>

We add elements/enqueue 5 elements to the queue :

  • q.queueEnqueue(10);
  • q.queueEnqueue(5);
  • q.queueEnqueue(8);
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  • q.queueEnqueue(2);

Printing this would give:

q. queueDisplay()

10, 5, 8, 9, 2

Next, we would remove elements/dequeue 2 elements from the queue :

q. queuedequeue();

q. queuedequeue();

Printing it would be:

q. queueDisplay()

8 ,9, 2

Observing this, the deletion/dequeue starts from the front/first index.

The remaining indices of the internal array elements are: 2, 3, 4 or 2 to 4

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3 0
2 years ago
What is the primary purpose of the software package offered by hyper-v called guest integration services?
zysi [14]

Solution:

Guest integration services resolves compatibility issues of certain guest operating systems experiencing non-functioning features.

Data integration service is the employment of a group of services that comply with service-oriented architecture. Data integration service can perform in an N -> 0 latency time period. At the same time, it offers a powerful set of transformation processes for meeting an array of business imperatives. The advantages of employing data integration as an enterprise service include reduced time for marketing, a reduction in total cost of ownership (TCO), and a solution to the obsolete and expensive data-integration patterns presently available in corporate businesses.

This is the required answer.

6 0
3 years ago
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