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Ksju [112]
3 years ago
10

How to get bing with any node unblocker

Computers and Technology
2 answers:
goldfiish [28.3K]3 years ago
7 0

Answer:

rawr xD

Explanation:

Reika [66]3 years ago
5 0

Answer:

<em><u>rawr</u></em><em><u> </u></em><em><u>xD</u></em><em><u> </u></em><em><u>broooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo</u></em>

Explanation:

  • <em><u>UwU</u></em>
  • <em><u>OwO</u></em>
  • <em><u><</u></em><em><u>3</u></em>
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For some reason my code is not printing in python. It doesn't give me an error is just not printing no thing shows up
svetoff [14.1K]

Answer:

Whats python? i might be able to help

Explanation:

5 0
3 years ago
Technologies that function within the established system are called
vesna_86 [32]
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</span>Obstructing technologies include blocking<span> and filtering, content manipulation, attacks.
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8 0
3 years ago
Write a C console application that will be used to determine if rectangular packages can fit inside one of a set of spheres. You
MatroZZZ [7]

Answer:

#include <cmath>

#include <iostream>

using namespace std;

int getSphereSize(double length, double breadth, double height) {

   double diagonal = sqrt(length * length + breadth * breadth + height * height);

   if (diagonal <= 4)

       return 4;

   if (diagonal <= 6)

       return 6;

   if (diagonal <= 8)

       return 8;

   if (diagonal <= 10)

       return 10;

   if (diagonal <= 12)

       return 12;

   return 0;

}

int main() {

   double length, breadth, height;

   int sphereCounts[5] = {0};

   int sphereSize;

   while (true) {

       // Get dimensions of the box

       cout << "Enter the dimensions of the box:\n";

       cout << "Length: ";

       cin >> length;

       cout << "Breadth: ";

       cin >> breadth;

       cout << "Height: ";

       cin >> height;

       if (length <= 0 || breadth <= 0 || height <= 0)

           break;

       sphereSize = getSphereSize(length, breadth, height);

       if (sphereSize == 0)

           cout << "The box cannot fit in any of the spheres";

       else

           cout << "The box can fit in the " << sphereSize << "-inch sphere";

       // Increment the counter

       if (sphereSize == 4)

           sphereCounts[0]++;

       else if (sphereSize == 6)

           sphereCounts[1]++;

       else if (sphereSize == 8)

           sphereCounts[2]++;

       else if (sphereSize == 10)

           sphereCounts[3]++;

       else if (sphereSize == 12)

           sphereCounts[4]++;

       cout << "\n\n";

   }

   cout << "\nNumber of 4-inch spheres: " << sphereCounts[0];

   cout << "\nNumber of 6-inch spheres: " << sphereCounts[1];

   cout << "\nNumber of 8-inch spheres: " << sphereCounts[2];

   cout << "\nNumber of 10-inch spheres: " << sphereCounts[3];

   cout << "\nNumber of 12-inch spheres: " << sphereCounts[4];

   cout << endl;

   return 0;

}

Explanation:

The "cmath" library is included in the c++ program. The getSphereSize function is used to return the sphere size the rectangle dimension can fit into. It program continuously prompts the user for the length, breadth, and height of the rectangle and passes the values to the getSphereSize function in the while but breaks if any or all of the variable value is zero.

The sizes of the sphere objects in inches are collected in an array of five integer values of zeros and are incremented by one for every match with a rectangle.

7 0
3 years ago
PLEASE HURRY
Katarina [22]

Answer:

1. 321 x 408 print (321 times 408)

Explanation:

It is multiplication, it will create a product. So that is why.

3 0
3 years ago
Read 2 more answers
Given a high-level code you should be able to write the corresponding MIPS assembly code. Simple loop in C; A[ ] is an array of
nevsk [136]

Answer:

Explanation:

The code for the given problem is written below

.data

A : .word 1 2 3 4 5 6 7 8 9 10

.text

la $s5,A

li $s1,0 # load g

li $s2,10 # load h

li $s3,0 # load i

li $s4,1 # load j

loop:

mul $s6,$s3,4

add $s6,$s6,$s5 #address of A[i]

lw $s6,($s6) #get value of A[i] in s3

add $s1,$s1,$s6 #g = g+A[i]

add $s3,$s3,$s4 # i = i+j

bne $s3,$s2,loop #if i!=h jump to loop

4 0
3 years ago
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