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wolverine [178]
4 years ago
12

Given four functions , which one will have the smallest y-interception

Mathematics
1 answer:
Sedaia [141]4 years ago
4 0
The four y-intercepts are {$6, $2, $4, $10}.  Which of these is the smallest?
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Ana uses Talk-A-Lot and Peter uses Talk-to-Me. Each company charges
mr Goodwill [35]

Answer:

They both talk for a different amount of time

7 0
3 years ago
PLEASE HELP!!!! Nicholas is buying shirts for his baseball team. He will pay $8.75 for each shirt plus a one-time fee of $25 for
Marizza181 [45]

Answer:

y = 8.75x + 25

Step-by-step explanation:

8 0
3 years ago
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∠A=5x−18. ∠B=3x+42∘ solve for x and then find the measure of ∠A
KatRina [158]

Answer:

x = 30 ∠A = 132 degrees

Step-by-step explanation:

Set the equations equal to each other to solve for x

5x - 18 = 3x + 42

-3x        - 3x               Subtract 3x from both sides

2x - 18 = 42

    + 18  + 18              Add 18 to both sides

2x = 60                     Divide both sides by 2

x = 30

Now plug this into the equation for angle A

∠A = 5(30) − 18        Multiply

∠A = 150 - 18           Subtract

∠A = 132 degrees

If this answer is correct, please make me Brainliest!

6 0
3 years ago
Read 2 more answers
The height of a stuntperson jumping off a building that is 20 m high is modeled by the equation h = 20 -57, where t is the time
cupoosta [38]

A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?

Answer:

1\leq t\geq \sqrt{2}

Step-by-step explanation:

Given:

A stuntman jumping off a 20-m-high building is modeled by the equation

h =20-5t^{2}-----------(1)

A high-speed camera is ready to making film between 15 m and 10 m above the ground

when the stuntman is 15m above the ground.

height h = 15m  

Put height value in equation 1

15 =20-5t^{2}

5t^{2} =20-15

5t^{2} =5

t^{2} =1

t =\pm1

We know that the time is always positive, therefore t=1

when the stuntman is 10m above the ground.

height h = 10m  

Put height value in equation 1

10 =20-5t^{2}

5t^{2} =20-10

5t^{2} =10

t^{2} =\frac{10}{5}

t^{2} =2

t=\pm\sqrt{2}

t=\sqrt{2}

Therefore ,time interval of camera film him is 1\leq t\geq \sqrt{2}

7 0
4 years ago
Evaluate the expression 3(7 + 4)2 − 14 ÷ 7. (5 points)
Kitty [74]
<span>3(7 + 4)2 − 14 ÷ 7

First do the parenthesis

7 + 4 = 11

so the question looks like: 3(11)2 - 14/7

Then multiply 3, 11, and 2 together

3 x 11 x 2 = 66

66 - 14/7

14/7 equals to 2

66 - 2 

Then just simplify

66 - 2 = 64

64 is your answer

hope this helps</span>
3 0
3 years ago
Read 2 more answers
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