Area of a cirlce=πr²
we have two radius:2r and r
area of the cirlce₁ + area of the circle₂=80 m²
area of the circle₁=π(2r)²
area of the circle₂=πr²
Then, we can suggest this quation:
π(2r)²+πr²=80
4πr²+πr²=80
π(4r²+r²)=80
π(5r²)=80
5πr²=80
r²=80/5π
r=√(80/5π)≈2.26
radius of the largest cirlce=2r=2(2.26)=4.51
Answer: the radius of the largest circle is 4.51 m
Answer:
15
Step-by-step explanation:
3x+15=60
3x=45
x=15
Answer:
<h2>The vessel in distress is located in between vessels A and B</h2>
Step-by-step explanation:
To describe how we arrive at the answer, we are going to use the drawing i have attached to this response.
southwest of ship A is just a distance around the third quadrant (using the cardinal point) and it is below A
North of B is few distances ahead of ship B.
<em>Please see the attached sketch </em>
The way I used to think to figure this out is to remember that a slope is "rise over run" or y over x (y/x). You'll want to find the change of y and the change of x. There is a change of -9 between 6 and -3. The change between -2 and 7 is 9 too. 9/-9 equals -1. So the slope is -1.
