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3 years ago

11

X^2+2x-15/x=x-1/2+x-1/x

1 answer:

ZanzabumX [31]3 years ago

7 0

Answer:

x=2.11872822

Step-by-step explanation:

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Henry counted 350 lockers in his school.Hayley counted 403 lockers in her school. How does the 3 in 350 compare to the 3 in 403?

arsen [322]

The 3 in 350 signifies 300 lockers. The 3 in 403 signifies just 3 lockers.

6 0

3 years ago

Read 2 more answers

Plz solve it And show ur work plzzz giving brainliest

miss Akunina [59]

Answer:

Step-by-step explanation:

4 x 6 1/4

4 x 25/4

= 25

5 0

3 years ago

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Tony was Challenged to a half-court shooting competition. For every half-court shot that he makes, he will earn 20 points. For e

Mkey [24]

Answer:

Tony make 4 half-court shots and misses 16 half-court shots.

Step-by-step explanation:

Given:

Points earned for every successful, half-court shots = $20$

Points deducted for missing the shots = $5$ or $-5$

Total number of shots in the game = $20$

Final points earned by Tony = $0$

According to the question:

Let the number of successful half-court shot be $x$

And the number of shots missed be $20-x$

So,

In terms of points we can re-write it as:

⇒ $20(x)-5(20-x) =0$

⇒ $20x-100+5x=0$

⇒ $25x-100=0$

⇒ $25x-100+100=100$

⇒ $25x=100$

⇒ $\frac{25x}{25} =\frac{100}{25}$

⇒ $x=\frac{100}{25}$

⇒ $x=4$

Tony make 'x' shots that is 4 and the number of shot he missed is (20-x) =(20-4)=16

6 0

3 years ago

Which expression gives the value of x?

tester [92]

Answer:

B

Step-by-step explanation:

7 0

3 years ago

Practice simplifying rational expressions with negative exponents.

Gelneren [198K]

Answer:

Part 1:- option first is correct

$-\frac{1}{2}ab^{12}$

Part 1:- option third is correct

$\frac{w^{10}}{3y^{4}}$

Step-by-step explanation:

Given:

The given ration expressions are.

1. $\frac{-2a^{2}b^{4}}{4ab^{-8}}$

2. $\frac{-5w^{4}y^{-2}}{-15w^{-6}y^{2}}$

We need to simplify the given expressions.

Solution:

Part 1:-

Given expression is

$=\frac{-2a^{2}b^{4}}{4ab^{-8}}$

Using law of exponents $\frac{x^{m} }{x^{n} } = x^{(m-n)}$

$=-\frac{a^{2-1}b^{4-(-8)}}{2}$

$=-\frac{a^{1}b^{4+8}}{2}$

$=-\frac{ab^{12}}{2}$

$=-\frac{1}{2}ab^{12}$

Therefore, option first $-\frac{1}{2}ab^{12}$ is correct.

Part 2:-

Given expression is.

$=\frac{-5w^{4}y^{-2}}{-15w^{-6}y^{2}}$

Using law of exponents $\frac{x^{m} }{x^{n} } = x^{(m-n)}$

$=\frac{w^{4-(-6)}y^{-2-2}}{3}$

$=\frac{w^{4+6}y^{-4}}{3}$

$=\frac{w^{10}y^{-4}}{3}$

$=\frac{w^{10}}{3y^{4}}$

Therefore, third option $\frac{w^{10}}{3y^{4}}$ is correct.

4 0

3 years ago