Answer:
There would be 9 roses.
Step-by-step explanation:
The ratio began as 3 to 5 so in all there were 8 flowers.
If there are 24 , being that 8 x 3 = 24, then all you have to is multiply both sides of the ratio by 3.
3 x 3 = 9
5 x 3 = 15
9 + 15 = 24
New ratio is 9 to 15
Answer:
February, it's the shortest month after all.
<h3>
Answer: 2 seconds</h3>
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Explanation:
I'll be using x in place of t
The equation given is y = -4.9x^2 + 19.8x + 58
It is of the form y = ax^2 + bx + c which is the standard form for quadratics.
We have,
Plug the first two values into the equation below
h = -b/(2a)
h = -19.8/(2*(-4.9))
h = 2.0204081632653
That value is approximate.
Rounding to the nearest whole number gets us roughly h = 2
Recall that (h,k) is the vertex of the parabola. In this case, it's the highest point. The cannonball reaches the highest point at roughly 2 seconds.
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Extra side notes:
- To find the maximum height, plug the h value into the original equation. This will yield the value of k.
- To find the cannonball's flight time, plug in y = 0 and solve for x. Ignore the negative x solution.
Answer:
31° is the measure of ang TDC
Average speed for the entire trip, both ways, is
(Total distance) divided by (total time) .
We don't know the distance from his house to the gift store,
and we don't know how long it took him to get back.
We'll need to calculate these.
-- On the trip TO the store, it took him 50 minutes, at 6 mph.
-- 50 minutes is 5/6 of an hour.
-- Traveling at 6 mph for 5/6 of an hour, he covered 5 miles.
-- The gift store is 5 miles from his house.
-- The total trip both ways was 10 miles.
-- On the way BACK home from the store, he moved at 12 mph.
-- Going 5 miles at 12 mph, it takes (5/12 hour) = 25 minutes.
Now we have everything we need.
Distance:
Going: 5 miles
Returning: 5 miles
Total 10 miles
Time:
Going: 50 minutes
Returning: 25 minutes
Total: 75 minutes = 1.25 hours
Average speed for the whole trip =
(total distance) / (total time)
= (10 miles) / (1.25 hours)
= (10 / 1.25) miles/hours
= 8 miles per hour
