All categories

3 years ago

Identify the function in which y varies directly with x.

Mathematics

1 answer:

Vera_Pavlovna [14]3 years ago

8 0

I'm pretty sure it is A. The others have the y-intercept added and c would just be y=0.

You might be interested in

WILL GIVE BRAINLIST ASAP PLZ HELP!!!

tamaranim1 [39]

Answer:

Step-by-step explanation:

I answered cause like you're my bsf on this page so yea...

5 0

3 years ago

Read 2 more answers

I need helppppp plzzzzzz

Alla [95]

I think the answer is B.

Rotating a polygon changes it’s location not size.

Hope this is helpful.

5 0

3 years ago

A circuit has a current of (8 + 7i) amps, and another circuit has a

Schach [20]

Answer:

Answer:  3 + 10i 

Step-by-step explanation:

$= { \rm{(8 + 7i) - (5 - 3i)}} \\ \\ = { \rm{(8 - 5) + (7 + 3)i}} \\ \\ { = \rm{3 + 10i}}$

8 0

2 years ago

Read 2 more answers

A delivery truck is delivering 28 cases of paper to a store. Each case has 50 packs of paper. In each pack of paper there are 20

olga2289 [7]

Answer:

Step-by-step explanation:

7 0

3 years ago

Solve this equation using all three methods 4x^ = 9

Bumek [7]

Answer:

$x=-\frac{3}{2}, x=\frac{3}{2}$

Step-by-step explanation:

(1) To solve by factoring,

Given equation: $4 x^{2}=9$

Subtract 9 from both sides of the equation.

$\begin{aligned}&4 x^{2}-9=9-9\\&4 x^{2}-9=0\\&(2 x)^{2}-3^{2}=0\\&(2 x-3)(2 x+3)=0\end{aligned}$

Using zero factor principle, $2 x-3=0,2 x+3=0$

The solutions are $x=-\frac{3}{2}, x=\frac{3}{2}$ .

(2) To solve by complete the square ,

Given $4 x^{2}=9$

Divide both sides of the equation by 4.

$\frac{4 x^{2}}{4}=\frac{9}{4}$

$\Rightarrow x^{2}=\frac{9}{4}$

Square root on both sides.

$\Rightarrow x=\pm \frac{3}{2}$

$x=-\frac{3}{2}, x=\frac{3}{2}$

(3) To solve by quadratic formula,

$4 x^{2}-9=0$

Here, a = 4, b = 0, c = –9

Quadratic formula, $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

$x=\frac{-0 \pm \sqrt{0^{2}-4 \times 4 \times(-9)}}{2 \times 4}$

$\begin{aligned}&\Rightarrow x=\frac{\pm \sqrt{144}}{8}\\&\Rightarrow x=\pm \frac{3}{2}\\&\Rightarrow x=\frac{3}{2}, x=-\frac{3}{2}\end{aligned}$

3 0

3 years ago