I’m on the way home I can see if I could have a good time at your house and I’ll
Based on the above:
The slope of P'Q' is = -3/2
The length of P'Q' is approximately = ![\sqrt[3]{13}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B13%7D)
<h3>What is the polygon about?</h3>
The slope of P'Q'
= -6/4 = -3/2
The length of P'Q' =
P'Q' = 
= 
= ![\sqrt[2]{13}](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B13%7D)
Therefore;
P'Q' = 
P'Q' = x
=
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Answer:
B) The maximum y-value of f(x) approaches 2
C) g(x) has the largest possible y-value
Step-by-step explanation:
f(x)=-5^x+2
f(x) is an exponential function.
Lim x→∞ f(x) = Lim x→∞ (-5^x+2) = -5^(∞)+2 = -∞+2→ Lim x→∞ f(x) = -∞
Lim x→ -∞ f(x) = Lim x→ -∞ (-5^x+2) = -5^(-∞)+2 = -1/5^∞+2 = -1/∞+2 = 0+2→
Lim x→ -∞ f(x) = 2
Then the maximun y-value of f(x) approaches 2
g(x)=-5x^2+2
g(x) is a quadratic function. The graph is a parabola
g(x)=ax^2+bx+c
a=-5<0, the parabola opens downward and has a maximum value at
x=-b/(2a)
b=0
c=2
x=-0/2(-5)
x=0/10
x=0
The maximum value is at x=0:
g(0)=-5(0)^2+2=-5(0)+2=0+2→g(0)=2
The maximum value of g(x) is 2
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❖ There are 180 inches in 5 yards.
1 yd = 36 in
36 x 5 = 180
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2x + 4 1/5 = 9
2x = 9 - 4 1/5
2x = 5 1/5
2x divided by 2 = x
5 1/5 divided by 2 = 13/5 (2 3/5, or 2.6)
x = 13/5 (2 3/5, or 2.6)
