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Pepsi [2]
3 years ago
8

If Hanna had 25 dollars and spends 2 how much money does she have

Mathematics
2 answers:
vaieri [72.5K]3 years ago
7 0
So you subtract 25 from 2
and you 23
Mama L [17]3 years ago
4 0

23

okayh help you are helping okahy from finland

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The question is below thanks
Paha777 [63]

Answer:

FH ~ 10.02

Step-by-step explanation:

1. Approach

One should first find the circumference of the given circle. Then one should find how large the fraction of the circumference one is supposed to find is. Finally, one should multiply the fraction of the circumference one is supposed to find by the total circumference.

2. Circumference of the circle

The formula for circumference is;

2rπ

Substitute in the given values;

It is given that the radius is, hence

2 (7) π

14π

3. Find the fraction of the circumference one is supposed to find

It is given that the angles over the measure of the total degrees of angles in a circle are equal to the arc surrounding the angles of the circumference. Essentially;

\frac{angles}{360}=\frac{arc}{circumference}

Substitute in the given information and solve;

\frac{82}{360}=\frac{arc}{14pi}

arc = \frac{41}{180}*14pi

arc = \frac{287}{90}*pi

arc ~ 10.02

3 0
3 years ago
3-4y=5x-6. The answer is (-5x^4-9)/4. Please explain how to get this.
xenn [34]

Answer:

The direction of mathematics teacher is study about the mathematics teacher is study about it is by step instructions

5 0
2 years ago
The half life of a radioactive substance is the time it takes for a quantity of the substance to decay to half of the initial am
Veronika [31]

Using an exponential function, it is found that:

a) N(t) = 75(0.5)^{\frac{t}{3.8}}

b) 37.5 grams of the gas remains after 3.8 days.

c) The amount remaining will be of 10 grams after approximately 11 days.

<h3>What is an exponential function?</h3>

A decaying exponential function is modeled by:

A(t) = A(0)(1 - r)^t

In which:

  • A(0) is the initial value.
  • r is the decay rate, as a decimal.

Item a:

We start with 75 grams, and then work with a half-life of 3.8 days, hence the amount after t daus is given by:

N(t) = 75(0.5)^{\frac{t}{3.8}}

Item b:

This is N when t = 3.8, hence:

N(t) = 75(0.5)^{\frac{3.8}{3.8}} = 37.5

37.5 grams of the gas remains after 3.8 days.

Item c:

This is t for which N(t) = 10, hence:

N(t) = 75(0.5)^{\frac{t}{3.8}}

10 = 75(0.5)^{\frac{t}{3.8}}

(0.5)^{\frac{t}{3.8}} = \frac{10}{75}

\log{(0.5)^{\frac{t}{3.8}}} = \log{\frac{10}{75}}

\frac{t}{3.8}\log{0.5} = \log{\frac{10}{75}}

t = 3.8\frac{\log{\frac{10}{75}}}{\log{0.5}}

t \approx 11

The amount remaining will be of 10 grams after approximately 11 days.

More can be learned about exponential functions at brainly.com/question/25537936

4 0
2 years ago
Type an equation for the line shown on the graph<br><br> (-2,-3) (2,3)
scoray [572]

Answer:

y = 1.5x

Step-by-step explanation:

5 0
3 years ago
Solve....... <img src="https://tex.z-dn.net/?f=5%20%282%29%20x%5E%7B2%7D%20-%206" id="TexFormula1" title="5 (2) x^{2} - 6" alt="
dsp73

10x^2-6 hope this helps

4 0
3 years ago
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