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3 years ago

(13÷6)×8+6. question 2. 10×3+(7+8) please show steps Thank you

Mathematics

2 answers:

Sergio039 [100]3 years ago

5 0

(13÷6)×8+6

first you need to divide the one in the parenthesis, so the answer will be

(13÷6)=2.16 then,

2.17×8+6

at that point you need to do the multiplacation first, 2.17×8.

2.17×8 = 17.36 then,

17.36 + 6 now you gonna add this numbers

so the answer is 23.36.

for the other question, the same thing do the one in the parenthesis first then the multiplication then the addition.

PEMDAS - Parenthesis, Exponent, Multiplication, Division, Addition, Subtraction

just follow this then you will got your answer.

AysviL [449]3 years ago

3 0

That is how u would do it

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I need another graphing quadratic pointer f(x)=x square -18x +80

swat32

F(x)=x^2-18x+80
ok so remember
you need to know
1. degree of function- tells what kind of graph
2. leading term- tells which direction graph opens
3. xintercept and y intercepts
4. vertex

ok so in form
f(x)=ax^2+bx+c

1.
degree, 2nd degree so parabola

2.
a=leading terma=+1 in this case so the graph opens up and is a normal graph

3.xintercept is where graph crosses x axis or where y=0, y=f(x) so
0=x^2-18x+80
0=(x-8)(x-10)
xints are (8,0) and (10,0)
y intercept is where cross y axis or where x=0
set x=0
yint=0^2-18(0)+80
yint=80
yint=(0,80)

4. vertex (vertex is highest point if graph opens down, and lowest point if graph opens up)
if in form f(x)=ax^2+bx+c, the x value of the vertex is given by -b/(2a) so
b=-18
a=1
-(-18)/2(1)
18/2=9
input
9^2-18(9)+80=yvalue
-1=yvalue
vertex=(9,-1)

so we have
1. graph is parabola
2. opens up
3. crosses through points (8,0), (10,0), (0,80)
4. vertex=(9,-1)

so we plot the points (8,0), (10,0), (0,80) and (9,-1) and draw a prabola opening up with (9,-1) as the highest point
attachment below ( it might be hard to graph (0,80) since it is so high up so you don't have to graph that point)

4 0

3 years ago

For lines a , c , and d , line c is parallel to line d and m ∠ 1 = 55 ° . Part A: For the given diagram, use the measure of ∠ 1

pentagon [3]

Answer:

Part A:

1, 4, 5, and 8 = 55 degrees.

3, 2, 6, and 7 = 125 degrees.

Part B:

I know that angle 1 is 55 degrees so angle 7 would be 125.

I know that angle 1 is 55 and to get angle 2, both angles should add up to 180 so 180 - 55 is 125, that is how I find angle 2 = 125 degrees.

Step-by-step explanation:

This is what I wrote, I hope it helps and tell me if I am wrong but I think it is right.

Have a Meowgical day!

6 0

2 years ago

Suppose that 11% of all steel shafts produced by a certain process are nonconforming but can be reworked (rather than having to

polet [3.4K]

Answer:

(a) The probability that X is at most 30 is 0.9726.

(b) The probability that X is less than 30 is 0.9554.

(c) The probability that X is between 15 and 25 (inclusive) is 0.7406.

Step-by-step explanation:

We are given that 11% of all steel shafts produced by a certain process are nonconforming but can be reworked. A random sample of 200 shafts is taken.

Let X = the number among these that are nonconforming and can be reworked

The above situation can be represented through binomial distribution such that X ~ Binom(n = 200, p = 0.11).

Here the probability of success is 11% that this much % of all steel shafts produced by a certain process are nonconforming but can be reworked.

Now, here to calculate the probability we will use normal approximation because the sample size if very large(i.e. greater than 30).

So, the new mean of X, $\mu$ = $n \times p$ = $200 \times 0.11$ = 22

and the new standard deviation of X, $\sigma$ = $\sqrt{n \times p \times (1-p)}$

= $\sqrt{200 \times 0.11 \times (1-0.11)}$

= 4.42

So, X ~ Normal( $\mu =22, \sigma^{2} = 4.42^{2}$ )

(a) The probability that X is at most 30 is given by = P(X < 30.5) {using continuity correction}

P(X < 30.5) = P( $\frac{X-\mu}{\sigma}$ < $\frac{30.5-22}{4.42}$ ) = P(Z < 1.92) = 0.9726

The above probability is calculated by looking at the value of x = 1.92 in the z table which has an area of 0.9726.

(b) The probability that X is less than 30 is given by = P(X $\leq$ 29.5) {using continuity correction}

P(X $\leq$ 29.5) = P( $\frac{X-\mu}{\sigma}$ $\leq$ $\frac{29.5-22}{4.42}$ ) = P(Z $\leq$ 1.70) = 0.9554

The above probability is calculated by looking at the value of x = 1.70 in the z table which has an area of 0.9554.

(c) The probability that X is between 15 and 25 (inclusive) is given by = P(15 $\leq$ X $\leq$ 25) = P(X < 25.5) - P(X $\leq$ 14.5) {using continuity correction}

P(X < 25.5) = P( $\frac{X-\mu}{\sigma}$ < $\frac{25.5-22}{4.42}$ ) = P(Z < 0.79) = 0.7852

P(X $\leq$ 14.5) = P( $\frac{X-\mu}{\sigma}$ $\leq$ $\frac{14.5-22}{4.42}$ ) = P(Z $\leq$ -1.70) = 1 - P(Z < 1.70)

= 1 - 0.9554 = 0.0446

The above probability is calculated by looking at the value of x = 0.79 and x = 1.70 in the z table which has an area of 0.7852 and 0.9554.

Therefore, P(15 $\leq$ X $\leq$ 25) = 0.7852 - 0.0446 = 0.7406.

5 0

3 years ago

PLEASE HELP ASAPP!!!!!!!!!!!!!!!

max2010maxim [7]

$\dfrac{1}{3^{-2}x^{-4}y^2}=\dfrac{3^2x^4}{y^2}\\\\\\
\dfrac{3^2\cdot3^4}{(-1)^2}=\dfrac{3^6}{1}=3^6=\boxed{729}$

Answer B)

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3 years ago

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If (x-1)/(x)=20 then x=

nadezda [96]

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3 years ago

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