M=0-5/1-0
m=-5/1=-5
y-y1=m*(x-x1)
y-5=-5(x-0)
y-5=-5x
y=-5x+5
1st it: g(2)=3(2)=6 || 2nd it: g^2(2)=3(6)=18 || 3rd it: g^3(2)=3(18)=54
Answer:
2ax − 6ay + bx − 3
Step-by-step explanation:
The expression is not factorable with rational numbers
Answer:
256
Step-by-step explanation:
4×4=16
16×4=64
64×4=256
Answer:
8.20in³
Step-by-step explanation:
Given V = πr²h
r is the radius = 1.5in
h is the height = 6in
thickness of wall of the cylinder dr = 0.04in
top and bottom thickness dh 0.07in+0.07in = 0.14in
To compute the volume, we will find the value of dV
dV = dV/dr • dr + dV/dh • dh
dV/dr = 2πrh
dV/dh = πr²
dV = 2πrh dr + πr² dh
Substituting the values into the formula
dV = 2π(1.5)(6)•(0.04) + π(1.5)²(6) • 0.14
dV = 2π (0.36)+π(1.89)
dV = 0.72π+1.89π
dV = 2.61π
dV = 2.61(3.14)
dV = 8.1954in³
Hence volume, in cubic inches, of metal in the walls and top and bottom of the can is 8.20in³ (to two dp)
