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qwelly [4]
2 years ago
13

Graph y=-2x+5 only please help quickly I’ll give brainliest to the quickest person

Mathematics
1 answer:
svlad2 [7]2 years ago
7 0

Answer:Slope:  − 2 y-intercept:  ( 0 , 5)x 0 5/2 y 5,0

Step-by-step explanation:

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Hi and hello have a nice day
Inga [223]

Answer:

Hey , stay safe <3

Step-by-step explanation:

Not sure if gif is working

8 0
3 years ago
A superhero recently asked his nemesis how many cats she has. she answered with a riddle: "seven eights" of my cats plus two" ho
ryzh [129]
<span>If the nemesis has "7/8 of her cats plus 2" it can be written like this: 7/8 x + 2 = x, where x is the number of the cats. After that we can solve the equation. x - 7/8 x = 2; 1/8 x = 2; x = 2 : 1/8 = 2 * 8 = 16. Answer: The nemesis has 16 cats.</span>
3 0
3 years ago
For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains
AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

f(x) = (1-p)^{x}p

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

\mu = \frac{1-p}{p}

The standard deviation of the geometric distribution is given by the following formula:

\sigma = \sqrt{\frac{1-p}{p^{2}}

In this problem, we have that:

p = 0.383

So

\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61

\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05

(a) What is the probability that a drought lasts exactly 3 intervals?

This is f(3)

f(x) = (1-p)^{x}p

f(3) = (1-0.383)^{3}*(0.383)

f(3) = 0.09

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is P = f(0) + f(1) + f(2) + f(3)

f(x) = (1-p)^{x}p

f(0) = (1-0.383)^{0}*(0.383) = 0.383

f(1) = (1-0.383)^{1}*(0.383) = 0.236

f(2) = (1-0.383)^{2}*(0.383) = 0.146

Previously in this exercise, we found that f(3) = 0.09

So

P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4).

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

P(X \leq 3) + P(X \geq 4) = 1

0.855 + P(X \geq 4) = 1

P(X \geq 4) = 0.145

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0
3 years ago
3(x-5)=9 i don't know what to do
Dafna1 [17]

Answer:

x=8

Step-by-step explanation:

3(x-5)=9

3x-15=9

3x-15+15=9+15

3x=24

x=8

8 0
2 years ago
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The solution to the system of linear equations is where the two lines intersect.

Look for the point where the two lines intersect. The x-value is 2 1/2, and the y-value is -4.

The answer is C.
5 0
3 years ago
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