All categories

2 years ago

+Given: AB ≅ AD and AB≅ AD AC≅ BD. Prove △BAE≅△DAE.

Mathematics

1 answer:

Daniel [21]2 years ago

8 0

Answer:

Step-by-step explanation:

Given:

AB ≅ AD

AC ⊥ BD

To Prove:

ΔBAE ≅ ΔDAE

Statements Reasons

1). AB ≅ AD and AC ⊥ BD 1). Given

2). AE ≅ AE 2). Reflexive property

3). ΔBAE ≅ ΔDAE 3). HL postulate of congruence

You might be interested in

A Japanese bullet train travels 558 miles per 3 hours A. What is the rate B. How far does the train travel in 1 hour WHO EVER A

Delicious77 [7]

Answer:

Step-by-step explanation:

Remark

The rate is going to be the same as the distance travelled in 1 hour. The units will be different.

Formula

d = r * t

Givens

d = 558 miles

t = 3 hours

Problem A

r = d / t

r = 558/ 3 = 186 miles / hr

Problem B

Givens

r = 186 miles / hour

t = 1 hour

d = ?

Solution

d = 186 mi/hr * 1 hr

d = 186 miles

Note

This looks really trivial, but it's not. You have to learn to see the difference between a number and its units. It's not very often that the numbers will be the same, but if the units differ, then it is an entirely different question.

7 0

2 years ago

Question 6 Express this decimal as a fraction. ? 1.21 = ^ it has a line over the 21.

saul85 [17]

Answer: 40/33

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

How long is a avarage school bus

Jlenok [28]

Answer:

School buses range anywhere from 20 to 45 feet in length ok?

5 0

2 years ago

Read 2 more answers

Before the pandemic cancelled sports, a baseball team played home games in a stadium that holds up to 50,000 spectators. When ti

spayn [35]

Answer:

(a) $D(x)=-2,500x+60,000$

(b) $R(x)=60,000x-2500x^2$

(d)Optimal ticket price: $12

Maximum Revenue:$360,000

Step-by-step explanation:

The stadium holds up to 50,000 spectators.

When ticket prices were set at $12, the average attendance was 30,000.

When the ticket prices were on sale for $10, the average attendance was 35,000.

(a)The number of people that will buy tickets when they are priced at x dollars per ticket = D(x)

Since D(x) is a linear function of the form y=mx+b, we first find the slope using the points (12,30000) and (10,35000).

$\text{Slope, m}=\dfrac{30000-35000}{12-10}=-2500$

Therefore, we have:

$y=-2500x+b$

At point (12,30000)

$30000=-2500(12)+b\\b=30000+30000\\b=60000$

Therefore:

$D(x)=-2,500x+60,000$

(b)Revenue

$R(x)=x \cdot D(x) \implies R(x)=x(-2,500x+60,000)\\\\R(x)=60,000x-2500x^2$

(c)To find the critical values for R(x), we take the derivative and solve by setting it equal to zero.

$R(x)=60,000x-2500x^2\\R'(x)=60,000-5,000x\\60,000-5,000x=0\\60,000=5,000x\\x=12$

The critical value of R(x) is x=12.

(d)If the possible range of ticket prices (in dollars) is given by the interval [1,24]

Using the closed interval method, we evaluate R(x) at x=1, 12 and 24.

$R(x)=60,000x-2500x^2\\R(1)=60,000(1)-2500(1)^2=\$57,500\\R(12)=60,000(12)-2500(12)^2=\$360,000\\R(24)=60,000(24)-2500(24)^2=\$0$

Therefore:

Optimal ticket price:$12
Maximum Revenue:$360,000

3 0

3 years ago

2^5×5×11 and 2^3×5^2×7

IceJOKER [234]

Answer:

1. 1760

2. 1400

Step-by-step explanation:

2^5 = 32

32 × 5 = 160

160 × 11 = 1760

2^3 = 8

5^2 = 25

8 × 25 = 200

200 × 7 = 1400

4 0

3 years ago