
In this triangle by applying Pythagoras theorem.
H²=B²+P²
18²=15²+P²
324=225+p²
324-225=P²
√99=p
9.94
s = hours it takes the small pipe on its own.
L = hours it takes the large pipe on its own.
we know the small pipe can do it in 11 hours total, so s = 11, so, how much of the whole job has the small done in 1 hour only?
well, if it takes 11 hours to do the whole thing, in 1 hour it has done only 1/11 of the whole job.
we know both pipes working together can do it in 6 hours flat. So in 1 hour only, both of them have done only 1/6 of the whole thing.
in that 1 hour, how much has the large one done? well, it has only done 1/L of the job.

and you can round that up as needed.
B. 2
if any other number was in there i dont think it would work because its neg
The tank is filling at
the rate of (58-36) in/(5-3 h) = 22/2 = 11 in/h.
72-58 = 14 inches more
to fill
<span>
The remaining 14 inches will be filled in
14 /11 = 1.27 , round to 1.3 hours</span>
so total time
would be 5 +1.3 = 6.3 hours
Answer:
1.76 liters/min
Step-by-step explanation:
while 105.6 liters is used in one hour, one hour is 60 min so divide 105.6 by 60 and you get 1.76 in one minute