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alukav5142 [94]
3 years ago
14

need help 5 minutes only answer this question: A line is defined by the equation 2 x + y = 4. Which shows the graph of this line

? There are 4 graphs.

Mathematics
2 answers:
Grace [21]3 years ago
6 0
It is the top left one because if you subtract 2x from both sides you will get a negative slope and the top one is the only one with a negative slope of 2x along with the y int 4.
Over [174]3 years ago
3 0

Answer:

I cant see your graphs because my admin blocked them but here.

Step-by-step explanation:

I hope this helps!

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Hello im a person
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Answer: i am a person

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Increase 220kg by 12.5%
Sidana [21]

Answer:

247.5kg

Step-by-step explanation:

u find 12.5% of 220, then add it

220*12.5% =27.5

220+27.5=247.5

3 0
3 years ago
Need help with this maybe question
Aleonysh [2.5K]

Answer:

the vertex is:

(2, -1)

Step-by-step explanation:

First solve the equation for the variable y

x^2-16y-4x-12=0

Add 16y on both sides of the equation

16y=x^2-16y+16y-4x-12

16y=x^2-4x-12

Notice that now the equation has the general form of a parabola

ax^2 +bx +c

In this case

a=1\\b=-4\\c=-12

Add (\frac{b}{2}) ^ 2 and subtract (\frac{b}{2}) ^ 2 on the right side of the equation

(\frac{b}{2}) ^ 2=(\frac{-4}{2}) ^ 2

(\frac{b}{2}) ^ 2=(-2) ^ 2

(\frac{b}{2}) ^ 2=4

16y=(x^2-4x+4)-4-12

Factor the expression that is inside the parentheses

16y=(x-2)^2-16

Divide both sides of the equality between 16

\frac{16}{16}y=\frac{1}{16}(x-2)^2-\frac{16}{16}

y=\frac{1}{16}(x-2)^2-1

For an equation of the form

y=a(x-h)^2 +k

the vertex is: (h, k)

In this case

h=2\\k =-1

the vertex is:

(2, -1)

6 0
3 years ago
River c is 500 miles longer than River d. The sum of their length is 5580 miles. What is the length for each river
diamong [38]

Answer:

I think it'll be 5080

Step-by-step explanation:

If the the river is 500 mil longer than the other wouldnt you subtract that by the sum 5580-500=5080

but i dont know  if thats right

8 0
3 years ago
How would you graph the solution set of the system of inequalities {3y≤2x+6} { 2x+y>0}
7nadin3 [17]
1) Solve the first inequality

3y ≤ 2x + 6

=> y ≤ 2x/3 + 2

2) Draw the line y = 2x/3 + 2

3) Shade the region below the line y = 2x/3 + 2

4) Solve the inequality 2x + y > 0

=> y > - 2x

5) draw the line y = -2x

6) Shade the region above the line y = -2x

7) The solution is the region between the two lines shaded including the portion of the line y = 2x/3 + 2
5 0
4 years ago
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