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3 years ago

In Bear Creek Bay in July, high tide is at 1:00 pm. The water level at

1 answer:

Studentka2010 [4]3 years ago

4 0

My trig is a bit rusty, but I'll give it a try:

$h=4-3\cos((t+5)\frac{\pi }{6})$

Here, h represents the height and t represents the time (as in 1:00, 2:00, etc.). The curve works, but it was after a bit of trial and error.

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Spinning an odd number and flipping heads.

Daniel [21]

Answer:

what

Step-by-step explanation:

4 0

3 years ago

Am I correct?? I did not count the last square unit at the vertices of each corner.

mariarad [96]

The answer would actually be a 110 units because the bottom left corner had 20 units and the bigger square had 90.

3 0

3 years ago

Sarah kicked a ball in the air. The function

Aleksandr-060686 [28]

Answer: The ball hits the ground at 5 s

Step-by-step explanation:

The question seems incomplete and there is not enough data. However, we can work with the following function to understand this problem:

$f=30 t- 6t^{2}$ (1)

Where $f$ models the height of the ball in meters and $t$ the time.

Now, let's find the time $t$ when the ball Sara kicked hits the ground (this is when $f=0 m$ ):

$0=30 t- 6t^{2}$ (2)

Rearranging the equation:

$6t^{2}-30 t=0$ (3)

Dividing both sides of the equation by $6$ :

$t^{2}-5 t=0$ (4)

This quadratic equation can be written in the form $at^{2}+bt+c=0$ , and can be solved with the following formula:

$t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$ (5)

Where:

$a=1$

$b=-5$

$c=0$

Substituting the known values:

$t=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(0)}}{2(1)}$ (6)

Solving we have the following result:

$t=5 s$ This means the ball hit the ground 5 seconds after it was kicked by Sara.

6 0

3 years ago

Hector is flying a kite. He has let out 86 feet

Kaylis [27]

Answer:

Hector's kite is 61.84 feet from the ground.

Step-by-step explanation:

The angle of elevation of the kite is 42°15’30” when converted to decimals, it is $42.258333^{0}$ ≅ $42.26^{0}$

Let the height of the kite to the horizontal of angle of elevation be represented as x. Applying the trigonometric function to the sketch of Hector's kite,

Sin θ = $\frac{opposite}{hypotenus}$

Sin $42.26^{0}$ = $\frac{x}{86}$

⇒ x = 86 x Sin $42.26^{0}$

= 86 x 0.6725

= 57.835

x ≅ 57.84 feet

The height of Hector's kite from the ground = x + 4

= 57.84 + 4

= 61.84 feet

7 0

3 years ago

A farmer has 520 feet of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one s

Setler [38]

Answer:

$310\text{ feet and }210\text{ feet}$

Step-by-step explanation:

GIVEN: A farmer has $520 \text{ feet}$ of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one side of the pen. The length of the barn is $310 \text{ feet}$ .