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Arte-miy333 [17]
4 years ago
7

4. What’s the answer to this question?

Mathematics
2 answers:
mixer [17]4 years ago
7 0

Answer: A

History will have 62,000 visitors in 2011 and Science will have 60,000 visitors in 2011

Alexandra [31]4 years ago
3 0

THE ANSWER IS A! Because it’s more in the 2000 era

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A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 434 gram setting. It is
yan [13]

Answer:

No, there is not sufficient evidence to support the claim that the bags are underfilled

Step-by-step explanation:

A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 434 gram setting.

This means that the null hypothesis is:

H_{0}: \mu = 434

It is believed that the machine is underfilling the bags.

This means that the alternate hypothesis is:

H_{a}: \mu < 434

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

434 is tested at the null hypothesis:

This means that \mu = 434

A 9 bag sample had a mean of 431 grams with a variance of 144.

This means that X = 431, n = 9, \sigma = \sqrt{144} = 12

Value of the test-statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{431 - 434}{\frac{12}{\sqrt{9}}}

z = -0.75

P-value of the test:

The pvalue of the test is the pvalue of z = -0.75, which is 0.2266

0.2266 > 0.01, which means that there is not sufficient evidence to support the claim that the bags are underfilled.

7 0
3 years ago
Which describes the cross section of the square prism that passes through the vertices A, B, C, and D shown below?
vagabundo [1.1K]

Answer:

The best option is;

A triangle with three equal sides all longer than 12 inches

Step-by-step explanation:

The cross sectional area of the square prism that passes through points A, B and C is found as follows;

Shape of cross section ABC = Triangle

Base, AB of the triangle is given by;

AB = √(8² + 8²) = √128 = 8·√2

Side, AC of the triangle is given by AC = √(8² + 12²) = 4√13

Therefore, the height of the triangle is given as follows;

Height, h = √(4·√13)²-(4·√2)² = 4·√11

The area of the cross section then is 0.5 × Base × Height

= 0.5 × 8·√2 × 4·√11  = 16·√22

A triangle with 3 equal sides of 8 inches has an area of 4×8×sin(60) = 16√3

A triangle with 2 equal sides of 12 inches and one side of 8 inches has an area of 4×12×sin(60) = 24√3

Therefore since 16·√22 > 24√3 >  16√3, the best option is a triangle with three equal sides of  (13\frac{1453}{8815}) all longer than 12 inches.

6 0
3 years ago
Explain how to subtract 7.6 from 20.39
ludmilkaskok [199]
<span>There are different methods of subtraction. Break up the sum into different parts. 20 - 7 is 13. 0.39 - 0.60 requires borrowing 1 unit from the 13 to make 1.39 - 0.60. This makes 0.79. Add the two results together: 12 + 0.79 = 12.79.</span>
7 0
4 years ago
A woman is buying bags of fruits and vegetables.
WITCHER [35]

Answer:

= $45

Step-by-step explanation:

$2.25 = 1 pound

$2.25 x 5 = 5 pounds

$11.25 = 5 pounds

$11.25 x 4 = 4 bags

$45 = 4 bags

Avocado out!!!!!!!!

------------------------------------------------------------------------------------

5 0
3 years ago
An opaque cylindrical tank with an open top has a diameter of 3.25 m and is completely filled with water. When the afternoon Sun
kicyunya [14]

Answer:

10.69

Step-by-step explanation:

We must first know that the angle of refraction is given by the following equation:

n_water * sin (A_water) = n_air * sin (A_air)

where n is the refractive index, for water it is 1.33 and for air it is 1.

The angle (A) in the air is 22.8 °, and that of the water is unknown.

Replacing these values we have to:

1.33 * sin (A_water) = 1 * 0.387

sin (A_water) = 1 * 0.387 / 1.33

A_water = arc sin (0.2907) = 16.9 °

now for the tank depth:

h = D / tan (A_water)

D = 3.25

Replacing

h = 3.25 / tan 16.9 °

h = 10.69

Therefore the depth is 10.69 meters.

6 0
3 years ago
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