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scoundrel [369]
3 years ago
15

PLEASE HELP ME QUESTION 7

Mathematics
1 answer:
KengaRu [80]3 years ago
8 0

The image shows the following:

  • adjacent = 6
  • opposite = 8 <em>(use Pythagorean Theorem)</em>
  • hypotenuse = 10

adjacent² + opposite² = hypotenuse²

       6²      + opposite² =         10²

      36      + opposite² =        100

                   opposite² =          64

                   opposite  =           8      

sin = \frac{opposite}{hypotenuse} = \frac{8}{10} = \frac{4}{5} <em>reduced</em>

cos = \frac{adjacent}{hypotenuse} = \frac{6}{10} = \frac{3}{5} <em>reduced</em>

tan = \frac{opposite}{adjacent} = \frac{8}{6} = \frac{4}{3} <em>reduced</em>

csc = \frac{hypotenuse}{opposite} = \frac{10}{8} = \frac{5}{4} <em>reduced</em>

sec = \frac{hypotenuse}{adjacent} = \frac{10}{6} = \frac{5}{3} <em>reduced</em>

cot = \frac{adjacent}{opposite} = \frac{6}{8} = \frac{3}{4} <em>reduced</em>

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</span>   4x + y = 16 
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