As with any "solve for ..." problem, you start by looking at the operations performed on the variable of interest. Here, when you evaluate this expression according to the order of operations, you
- add b1
- multiply by (h/2)
When you want to solve for b2, you undo these operations in reverse order. To undo multiplication by a fraction, you multiply by the inverse (reciprocal) of the fraction. To undo addition, you add the opposite.
Whatever you do must be done to both sides of the equation.
Here we go ...
... (2/h)A = b1 + b2 . . . . . we undid the multiply by h/2, by multiplying by 2/h
... (2/h)A - b1 = b2 . . . . . we undid the addition of b1 by adding the opposite of b1
Then your solution is
... b2 = 2A/h - b1
If you want to, you can combine these terms over a single denominator to get
... b2 = (2A -h·b1)/h
Answer:
DE =16CM while doing the Woking I used sohcah toa then I calculated de first and it gave me 16cm and ef gave me 13.85 which is not in the option
Answer:
15
Step-by-step explanation:
Okay, so we know that Base*Length=Area, so we just have to divide the area by the base, so the formula here is Area/Base=Length.
That would get us 120/8=Length,
and if we just divide 120 by 8 we get 15, so the length is 15
Options C and D as there is already a relationship between the numbers 1 and 2.
