Answer:
Horizontal asymptote of the graph of the function f(x) = 25/1+4x is y=0
Step-by-step explanation:
I attached the graph of the function. Graphically it can be seen that the horizontal asymptote of the graph of the function is y=0. There is also a <em>vertical</em> asymptote at x=-1/4
When denominator's degree (1) is higher than nominator's degree (0) then the horizontal asymptote is y=0
4b + 22 = 5 (b + 4) - 1 (remove the parantheses)
4b + 22 = 5b + 20 - 1 (calculate)
4b + 22 = 5b + 19 (move the terms)
4b - 5b = 19 - 22 (collect like terms and calculate)
-b = -3 (change the signs)
<em>b = 3</em>
Answer:
The answer would be B. 12 + 6n is greater than or equal to 30, so n is less than or equal to 3.
explanation:
I'm bad with explaining things, but I'll try my best to explain why this is the right answer.
12 + 6n ≥ 30, so n ≤ 3
let's start with the 12 at the beginning of the inequality, Annie already has $12, so the 12 in the inequality shows the amount of money she already has being added to the $6 per hour of babysitting she needs to do (n).
Now for the + 6n, the plus is there to show that the $12 Annie already has is being added to the 6n. The 6n then represents the $6 Annie makes each hour and the n represents how many hours she needs to babysit in order to get $30. The 6 is being multiplied by the amount of hours she needs to babysit to show how much money Annie would make. Then you add on the $12 she already has.
Annie then needs at least $30, but if she makes more than $30 then she will simply have more money than needed, therefore you use the greater than or equal to sign to show that she can have more money than just $30 after working.
I hope this helps, and sorry if my explanation is hard to understand lol.
Answer:
Step-by-step explanation:
From the given information:
We are to find the following:
1)
Directional hypothesis: The directional hypothesis is the groups with different bedroom lightning conditions having a different proportion of eyesight proportions.
2)
The non directional hypothesis is each group having the same proportion of eyesight problems regardless and independent of the condition of the bedroom lightning.
3)
Control group: Children that slept in darkness
4)
Experimental groups: Children that slept in night light and those that slept with lamp.
5)
Independent variable: Light condition of the bedroom
Dependent variable: Eye sight problem.
To find equivalent expressions,
distribute the first one and
factor the second one.
